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Bootstrap 3 - Why is row class is wider than its container?
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152
In all grid systems, there are gutters between each column. Bootstrap's system sets a 15px pad...
Extract public/private key from PKCS12 file for later use in SSH-PK-Authentication
...VATE KEY-----'
– edthethird
Aug 27 '15 at 17:27
4
To do that you could try openssl rsa -in privat...
Rails DB Migration - How To Drop a Table?
...opProductsTable
This will generate a .rb file in /db/migrate/ like 20111015185025_drop_products_table.rb
Now edit that file to look like this:
class DropProductsTable < ActiveRecord::Migration
def up
drop_table :products
end
def down
raise ActiveRecord::IrreversibleMigration
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Software keyboard resizes background image on Android
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edited Apr 4 '16 at 11:15
Basheer AL-MOMANI
10.8k88 gold badges7575 silver badges7676 bronze badges
a...
How to see if an object is an array without using reflection?
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You can use instanceof.
JLS 15.20.2 Type Comparison Operator instanceof
RelationalExpression:
RelationalExpression instanceof ReferenceType
At run time, the result of the instanceof operator is true if the value of the RelationalExpression is not...
JavaScript exponents
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answered Nov 18 '15 at 20:04
Salvador DaliSalvador Dali
169k116116 gold badges609609 silver badges691691 bronze badges
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Why is a round-trip conversion via a string not safe for a double?
...006, which is your original number -- so it compares equal, and hence only 15 digits are returned.
However, if I truncate the string at that zero to 84551240822557, then I get back 0.84551240822556994, which is not your original number, and hence it would return 17 digits.
Proof: run the following...
Bootstrap modal appearing under background
...other idea?
– Tuan Anh Tran
Feb 24 '15 at 7:18
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show 14 more comments
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Does MySQL ignore null values on unique constraints?
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Mark ByersMark Byers
683k155155 gold badges14681468 silver badges13881388 bronze badges
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How to find all occurrences of a substring?
...m.start() for m in re.finditer('test', 'test test test test')]
#[0, 5, 10, 15]
If you want to find overlapping matches, lookahead will do that:
[m.start() for m in re.finditer('(?=tt)', 'ttt')]
#[0, 1]
If you want a reverse find-all without overlaps, you can combine positive and negative lookah...