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Compiling with g++ using multiple cores
...ores busy.
If you have additional machines available too, you might check out distcc, which will farm compiles out to those as well.
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IsNothing versus Is Nothing
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Partial article contents: After reviewing more code I found out another reason you should avoid this: It accepts value types! Obviously, since IsNothing() is a function that accepts an 'object', you can pass anything you want to it. If it's a value type, .NET will box it up into an ob...
How to open a web page from my application?
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I used this as well, but now it turns out this doesn't work with UAC. In my application I have this in the manifest <requestedExecutionLevel level="requireAdministrator" uiAccess="false" /> When I run the app under Windows 8 (where you cannot disable UAC...
Why is spawning threads in Java EE container discouraged?
One of the first things I've learned about Java EE development is that I shouldn't spawn my own threads inside a Java EE container. But when I come to think about it, I don't know the reason.
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Include constant in string without concatenating
Is there a way in PHP to include a constant in a string without concatenating?
12 Answers
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How to make an element width: 100% minus padding?
...neral, wrapping elements in an extra div is a good way to pad elements without pushing the overall width of the element beyond it's parent container.
– Jake Wilson
Aug 23 '11 at 22:13
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Get visible items in RecyclerView
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First / last visible child depends on the LayoutManager.
If you are using LinearLayoutManager or GridLayoutManager, you can use
int findFirstVisibleItemPosition();
int findFirstCompletelyVisibleItemPosition();
int findLastVisibleItemPosition();
int findLastCompletelyV...
How to convert Set to String[]?
I need to get a String[] out of a Set<String> , but I don't know how to do it. The following fails:
7 Answers
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Spring Data: “delete by” is supported?
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Hi. If you are pointing out RBAR (row by agonizing row), could you add that to your answer? (and I'll upvote). I am kinda guessing at what you are pointing out here.
– granadaCoder
May 20 at 7:06
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What is “the inverse side of the association” in a bidirectional JPA OneToMany/ManyToOne association
...rs (orders are a list in the customer object). There can't be an order without a customer. So the customer seems to be the owner of the orders.
But in the SQL world, one item will actually contain a pointer to the other. Since there is 1 customer for N orders, each order contains a foreign key to t...