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Why can't I have “public static const string S = ”stuff"; in my Class?

... @jjnguy: Why? readonly is actually more flexible than Java's final for variables - you can set it as many times as you like in the constructor, but not elsewhere. That can be very handy. – Jon Skeet Jan 2 '09 at 23:01 ...
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How to display request headers with command line curl

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Why are Where and Select outperforming just Select?

... is the cost of constructing the new state of the where iterator, which is more complex than the simple iterator that the Select version uses. As you can see, for a given n, the Select version is a constant, whereas the Where+Select version is a linear equation with p(valid) as a variable. The act...
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How to detect pressing Enter on keyboard using jQuery?

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Can you help me understand this? “Common REST Mistakes: Sessions are irrelevant”

... not any brilliant reason i say, just for more security and more control. – EvilThinker Nov 24 '15 at 15:51 ...
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Git diff between current branch and master but not including unmerged master commits

...ast two forms that use ".." notations, can be any <tree>. For a more complete list of ways to spell <commit>, see "SPECIFYING REVISIONS" section in gitrevisions[7]. However, "diff" is about comparing two endpoints, not ranges, and the range notations ("<commit>..<commit>...
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Why do I have to access template base class members through the this pointer?

...e unless somehow specified to be an object), or that the default should be more context sensitive (in std::string s = "";, std::string could be read as a type since nothing else makes grammatical sense, even though std::string *s = 0; is ambiguous). Again, I don't know quite how the rules were agree...
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Is #pragma once part of the C++11 standard?

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Is there any way I can define a variable in LaTeX?

...text to insert} Then you can just use \newCommandName{} in the text For more info on \newcommand, see e.g. wikibooks Example: \documentclass{article} \newcommand\x{30} \begin{document} \x \end{document} Output: 30 s...
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Accessing an array out of bounds gives no error, why?

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