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How do I read a text file of about 2 GB? [duplicate]

I have a .txt file whose memory is more than 2 GB. The problem is I cannot open it with Notepad, Notepad++ or any other editor programs. ...
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How to access the ith column of a NumPy multidimensional array?

... 724 >>> test[:,0] array([1, 3, 5]) Similarly, >>> test[1,:] array([3, 4]) l...
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Static variables in member functions

...etime of i will remain through out the program. To add an example: A o1, o2, o3; o1.foo(); // i = 1 o2.foo(); // i = 2 o3.foo(); // i = 3 o1.foo(); // i = 4 share | improve this answer | ...
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Can't update Macports (with Mac OS X Mavericks)

... 282 Install the "Command Line Tools" first: sudo xcode-select --install (Explicitly agreeing to...
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Are there any standard exit status codes in Linux?

...f the killing signal are mixed into a single value on the return from wait(2) & co.. #include <stdio.h> #include <stdlib.h> #include <sys/types.h> #include <sys/wait.h> #include <unistd.h> #include <signal.h> int main() { int status; pid_t child = f...
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Python timedelta in years

...lace(year=from_date.year - years) except ValueError: # Must be 2/29! assert from_date.month == 2 and from_date.day == 29 # can be removed return from_date.replace(month=2, day=28, year=from_date.year-years) If it's 2/29, and 18 years ago...
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Invalid syntax when using “print”? [duplicate]

... 232 That is because in Python 3, they have replaced the print statement with the print function. ...
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Python - Count elements in list [duplicate]

... | edited Dec 4 '14 at 23:26 Charlie 6,5134545 silver badges5050 bronze badges answered Nov 9 '10 at ...
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How do we determine the number of days for a given month in python [duplicate]

...ulate the number of days for a given month in python. If a user inputs Feb 2011 the program should be able to tell me that Feb 2011 has 28 days. Could any one tell me which library I should use to determine the length of a given month. ...
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Iterating over a numpy array

...think you're looking for the ndenumerate. >>> a =numpy.array([[1,2],[3,4],[5,6]]) >>> for (x,y), value in numpy.ndenumerate(a): ... print x,y ... 0 0 0 1 1 0 1 1 2 0 2 1 Regarding the performance. It is a bit slower than a list comprehension. X = np.zeros((100, 100, 100)) %...