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Is there an R function for finding the index of an element in a vector?

...rks on vectors : x <- sample(1:10) x # [1] 4 5 9 3 8 1 6 10 7 2 match(c(4,8),x) # [1] 1 5 match only returns the first encounter of a match, as you requested. It returns the position in the second argument of the values in the first argument. For multiple matching, %in% is the way to...
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Is there a way to pass optional parameters to a function?

... The Python 2 documentation, 7.6. Function definitions gives you a couple of ways to detect whether a caller supplied an optional parameter. First, you can use special formal parameter syntax *. If the function definition has a formal p...
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Return two and more values from a method

... amenthes 2,7672828 silver badges3636 bronze badges answered Dec 25 '09 at 11:35 Aditya MukherjiAditya Mukherji...
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How to split a sequence into two pieces by predicate?

... By using partition method: scala> List(1,2,3,4).partition(x => x % 2 == 0) res0: (List[Int], List[Int]) = (List(2, 4),List(1, 3)) share | improve this answer ...
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Logging framework incompatibility

... 112 You are mixing the 1.5.6 version of the jcl bridge with the 1.6.0 version of the slf4j-api; this...
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Finding the index of elements based on a condition using python list comprehension

...t all, but just deal with the values—[value for value in a if value > 2]. Usually dealing with indexes means you're not doing something the best way. If you do need an API similar to Matlab's, you would use numpy, a package for multidimensional arrays and numerical math in Python which is heavi...
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How to append multiple values to a list in Python

...ny other thing that provides a sequence of values. >>> lst = [1, 2] >>> lst.append(3) >>> lst.append(4) >>> lst [1, 2, 3, 4] >>> lst.extend([5, 6, 7]) >>> lst.extend((8, 9, 10)) >>> lst [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] >>> lst...
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How do I replace NA values with zeros in an R dataframe?

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Regex to match a digit two or four times

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Unique combination of all elements from two (or more) vectors

... this maybe what you are after > expand.grid(a,b) Var1 Var2 1 ABC 2012-05-01 2 DEF 2012-05-01 3 GHI 2012-05-01 4 ABC 2012-05-02 5 DEF 2012-05-02 6 GHI 2012-05-02 7 ABC 2012-05-03 8 DEF 2012-05-03 9 GHI 2012-05-03 10 ABC 2012-05-04 11 DEF 2012-05-04 12 GHI 2012-0...