大约有 47,000 项符合查询结果(耗时:0.0545秒) [XML]
Is there a way to 'uniq' by column?
...imiter
-k1,1 for the key field 1
Test result:
overflow@domain2.com,2009-11-27 00:58:29.793000000,xx3.net,255.255.255.0
stack2@domain.com,2009-11-27 01:05:47.893000000,xx2.net,127.0.0.1
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import statistics
statistics.mean(l) # 20.11111111111111
On older versions of Python you can do
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On Python 2 you need to convert len to a float to get float division
sum(l) / float(len(l))
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