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How to filter (key, value) with ng-repeat in AngularJs?
...t present anymore. Is there a replacement, because the filter filter still does not allow objects?
– trysis
Dec 1 '15 at 15:28
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Passing a dictionary to a function as keyword parameters
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It does answer the question though, it just doesn't do it via dictionary unpacking. His approach is perfectly valid based on the question posted.
– Natecat
Nov 30 '16 at 1:19
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Get the cartesian product of a series of lists?
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What is the use of * before somelists? What does it do?
– Vineet Kumar Doshi
Aug 25 '15 at 9:04
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Age from birthdate in python
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@GrijeshChauhan: Yes, yours doesn't work. datetime.date(2014, 1, 1) gives -1, it should give 0. Your today > dob is checking if the DOB is in the past, not earlier this same year. datetime.date.today() includes year information, which is why I replac...
How can I declare and define multiple variables in one line using C++?
...sterisks next to the variable name instead of the type, but that in itself doesn't make any sense. Like I said above, the asterisk is part of the type, not part of the name, so it should by grouped with the type!
– Cam Jackson
Oct 28 '13 at 13:32
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mysql Foreign key constraint is incorrectly formed error
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@nawfal - I believe it does not necessarily have to be a primary key, but it MUST have an index. Primary keys automatically get indexed.
– Itai
May 6 '18 at 7:23
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Rename a dictionary key
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this works beautifully, but does not maintain the original order because the new key gets added at the end by default (in python3).
– szeitlin
Oct 1 '18 at 21:14
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MySQL Database won't start in XAMPP Manager-osx
... computer. Ever since, MySQL won't start in my manager-osx application. It doesn't throw me an in the application log. This is what it says:
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How to find out if a Python object is a string?
...r(b) == b where b holds the same data as str(b) but (being a bytes object) does not validate as a string.
– Tcll
Dec 6 '19 at 0:18
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jQuery Validate Required Select
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To help future readers: Where is says SelectName it does mean the value of the name attribute and not the value of the id attribute. This is a bit confusing since when working in JS one usually works with the id and not the name. See documentation here: "rules (default: rules ...