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Is it possible to use argsort in descending order?

...d(100) &gt;&gt;&gt; n = 30 &gt;&gt;&gt; timeit (-avgDists).argsort()[:n] 1.93 µs ± 6.68 ns per loop (mean ± std. dev. o<em>fem> 7 runs, 1000000 loops <em>eacem>h) &gt;&gt;&gt; timeit avgDists.argsort()[::-1][:n] 1.64 µs ± 3.39 ns per loop (mean ± std. dev. o<em>fem> 7 runs, 1000000 loops <em>eacem>h) &gt;&gt;&gt; timeit ...
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JSON datetime between Python and JavaScript

...27 Gokul 67222 gold badges1212 silver badges2626 bronze badges answered Jan 18 '09 at 22:26 maxmax ...
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UT<em>Fem>-8 byte[] to String

...uctor <em>fem>or converting byte array to string. byte[] byteArray = new byte[] {87, 79, 87, 46, 46, 46}; String value = new String(byteArray, "UT<em>Fem>-8"); share | improve this answer | ...
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How do I run a Python program?

...:18 Matt 67.9k2020 gold badges137137 silver badges171171 bronze badges answered Oct 5 '09 at 21:52 OscarRyzOsc...
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基于Windows平台的反Rootkit原理与实现 PD<em>Fem> - 文档下载 - 清泛网 - 专注C/C++及内核技术

............................. ................................ .............. 67 9.1 为什么需要验证 ................................ ................................ .............................. 67 9.2 RSA 9.2 RSA9.2 RSA加密算法 ................................ .............................
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How to print pandas Data<em>Fem>rame without index

... Pavol ZibritaPavol Zibrita 2,38411 gold badge88 silver badges44 bronze badges 9 ...
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How to take screenshot with Selenium WebDriver

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How exactly does a generator comprehension work?

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How to run a program without an operating system?

...er example, and replace the kernel with this one: https://github.com/dwelch67/raspberrypi/tree/<em>bcem>e377230c2cdd8<em>fem><em>fem>1e40919<em>fem>ded<em>bcem>2533e<em>fem>5a00/uart01 <em>Fem>irst get the UART working with Raspbian as I've explained at: https://raspberrypi.stackexchange.com/questions/38/prepare-<em>fem>or-ssh-without-a-screen/54394#5439...
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Counting the number o<em>fem> elements with the values o<em>fem> x in a vector

...gt; a &lt;- table(numbers) &gt; a numbers 4 5 23 34 43 54 56 65 67 324 435 453 456 567 657 2 1 2 2 1 1 2 1 2 1 3 1 1 1 1 Then you can subset it: &gt; a[names(a)==435] 435 3 Or convert it into a data.<em>fem>rame i<em>fem> you're more com<em>fem>ortable working with that...