大约有 47,000 项符合查询结果（耗时：0.0903秒） [XML]
Java 7 language features with Android
...y without any patches. Try-with-resource requires API Level 19+, and NIO 2.0 stuff are missing.
If you can't use Java 7 features, see @Nuno's answer on how to edit your build.gradle.
The following is for historical interest only.
A small part of Java 7 can certainly be used with Android (note:...
Use IntelliJ to generate class diagram
How do I get IntelliJ 10.5 (on the Mac) to generate a class diagram showing all of the classes in my project? I'm sure I'm overlooking something obvious, but I can only get the "Show Diagram" feature to show one class at a time. (I also figured out how to add additional classes, but again, only on...
std::string to char*
...
700
It won't automatically convert (thank god). You'll have to use the method c_str() to get the C ...
How do you check what version of SQL Server for a database using TSQL?
...
Try
SELECT @@VERSION
or for SQL Server 2000 and above the following is easier to parse :)
SELECT SERVERPROPERTY('productversion')
, SERVERPROPERTY('productlevel')
, SERVERPROPERTY('edition')
From: http://support.microsoft.com/kb/321185
...
How to import multiple .csv files at once?
...
A5C1D2H2I1M1N2O1R2T1A5C1D2H2I1M1N2O1R2T1
170k2424 gold badges348348 silver badges432432 bronze badges
...
Bootstrap 3.0 - Fluid Grid that includes Fixed Column Sizes
...
answered Oct 7 '13 at 20:21
Steve K.Steve K.
69711 gold badge66 silver badges88 bronze badges
...
Connect Java to a MySQL database
...
answered May 15 '10 at 9:10
Sean OwenSean Owen
62.6k1919 gold badges130130 silver badges163163 bronze badges
...
Is there a MySQL option/feature to track history of changes to records?
...
|
edited Apr 10 '18 at 11:24
Octavian Catusanu
13911 gold badge11 silver badge1313 bronze badges
...
JQuery to check for duplicate ids in a DOM
...{
var ids = $('[id="'+this.id+'"]');
if(ids.length>1 && ids[0]==this)
console.warn('Multiple IDs #'+this.id);
});
share
|
improve this answer
|
follow
...
Add new field to every document in a MongoDB collection
...gt; db.foo.insert({"test":"a"})
> db.foo.find()
{ "_id" : ObjectId("4e93037bbf6f1dd3a0a9541a"), "test" : "a" }
> item = db.foo.findOne()
{ "_id" : ObjectId("4e93037bbf6f1dd3a0a9541a"), "test" : "a" }
> db.foo.update({"_id" :ObjectId("4e93037bbf6f1dd3a0a9541a") },{$set : {"new_field":1}})
&g...