大约有 46,000 项符合查询结果(耗时:0.0276秒) [XML]
Generate random numbers with a given (numerical) distribution
...to numpy.random.choice(), e.g.
numpy.random.choice(numpy.arange(1, 7), p=[0.1, 0.05, 0.05, 0.2, 0.4, 0.2])
If you are using Python 3.6 or above, you can use random.choices() from the standard library – see the answer by Mark Dickinson.
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Easy pretty printing of floats in python?
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102
As noone has added it, it should be noted that going forward from Python 2.6+ the recommended w...
CSS Font Border?
...
1030
There's an experimental CSS property called text-stroke, supported on some browsers behind a -...
How can I repeat a character in Bash?
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410
You can use:
printf '=%.0s' {1..100}
How this works:
Bash expands {1..100} so the command be...
How to scale down a range of numbers with a known min and max value
...l. I want the height and width of each ellipse to be in a range of say 1-30. I have methods that find the minimum and maximum values from my data set, but I won't have the min and max until runtime. Is there an easy way to do this?
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Determine the data types of a data frame's columns
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220
Your best bet to start is to use ?str(). To explore some examples, let's make some data:
set...
How to check if a number is a power of 2
...his problem:
bool IsPowerOfTwo(ulong x)
{
return (x & (x - 1)) == 0;
}
Note, this function will report true for 0, which is not a power of 2. If you want to exclude that, here's how:
bool IsPowerOfTwo(ulong x)
{
return (x != 0) && ((x & (x - 1)) == 0);
}
Explanation
Fi...
initialize a numpy array
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answered Dec 26 '10 at 20:56
KatrielKatriel
102k1717 gold badges120120 silver badges157157 bronze badges
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How to darken a background using CSS?
...t black, faked with gradient */
linear-gradient(
rgba(0, 0, 0, 0.7),
rgba(0, 0, 0, 0.7)
),
/* bottom, image */
url(http://fc02.deviantart.net/fs71/i/2011/274/6/f/ocean__sky__stars__and_you_by_muddymelly-d4bg1ub.png);
}
Reference...
Extracting specific columns in numpy array
... |
edited Aug 23 at 10:39
cs95
231k6060 gold badges391391 silver badges456456 bronze badges
answere...