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Multiple returns from a function
...ered Aug 10 '10 at 17:59
dockeryZdockeryZ
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Calculate the center point of multiple latitude/longitude coordinate pairs
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Is R's apply family more than syntactic sugar?
...nd since a variable's state depends on the history.
Edit:
Just to emphasize this with a trivial example that recursively calculates the Fibonacci sequence; this could be run multiple times to get an accurate measure, but the point is that none of the methods have significantly different performanc...
What's the difference between a proxy server and a reverse proxy server? [closed]
...client" computer on the internet
Y = the proxy web site, proxy.example.org
Z = the web site you want to visit, www.example.net
Normally, one would connect directly from X --> Z.
However, in some scenarios, it is better for Y --> Z on behalf of X,
which chains as follows: X --> Y --> Z...
How to use z-index in svg elements?
... x and y axis of the SVG viewport, SVG elements are also positioned on the z axis. The position on the z-axis defines the order that they are painted.
Along the z axis, elements are grouped into stacking contexts.
3.4.1. Establishing a stacking context in SVG
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Stacking context...
z-index not working with position absolute
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The second div is position: static (the default) so the z-index does not apply to it.
You need to position (set the position property to anything other than static, you probably want relative in this case) anything you want to give a z-index to.
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What is the difference between .*? and .* regular expressions?
... matching anything but a greater-than sign (strictly speaking, it matches zero or more characters other than > in-between < and >).
See Quantifier Cheat Sheet.
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How do I change the value of a global variable inside of a function
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C++ stl stack/queue 的使用方法 - C/C++ - 清泛网 - 专注C/C++及内核技术
...当栈空时，返回true。
访问栈中的元素个数，如例：s.size()。
2、queue
queue 模板类的定义在<queue>头文件中。
与stack 模板类很相似，queue 模板类也需要两个模板参数，一个是元素类型，一个容器类型，元素类型是必要的，容器...
How to refresh app upon shaking the device?
... {
float x = se.values[0];
float y = se.values[1];
float z = se.values[2];
mAccelLast = mAccelCurrent;
mAccelCurrent = (float) Math.sqrt((double) (x*x + y*y + z*z));
float delta = mAccelCurrent - mAccelLast;
mAccel = mAccel * 0.9f + delta; // perform low-cut...