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Ruby: How to iterate over a range, but in set increments?

...) range.step(2) {|x| puts x} range.step(3) {|x| puts x} produces: 1 x 3 xxx 5 xxxxx 7 xxxxxxx 9 xxxxxxxxx 1 x 4 xxxx 7 xxxxxxx 10 xxxxxxxxxx Reference: http://ruby-doc.org/core/classes/Range.html ...... share ...
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Visual Studio: How do I show all classes inherited from a base class?

... I got an error saying "There are no types that derive from XXX in the current project", so I think it's limited to types in the current project, not the solution – Andy Mar 9 '16 at 12:54 ...
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Can't connect to localhost on SQL Server Express 2012 / 2016

...me as you. I had even disabled firewall, and nothing worked. There was a 40xxx port in TCP Dynamic Ports. I removed it, and put 1433 in TCP Port for IPAll, this did it as well. Thanks! – Alisson Jul 18 '16 at 23:23 ...
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How to get domain URL and application name?

... 91 The web application name (actually the context path) is available by calling HttpServletrequest...
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How to increase storage for Android Emulator? (INSTALL_FAILED_INSUFFICIENT_STORAGE)

... @MLindsay I agree – mwa91 Feb 5 '19 at 15:33 Just FYI, I didn't have to delete *.img or ...
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Remove all the elements that occur in one list from another

... DonutDonut 91.2k1717 gold badges123123 silver badges138138 bronze badges ...
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How to add test coverage to a private constructor?

...s. If you can use Java 8, then you can use interface instead. package com.XXX; public interface Foo { public static int bar() { return 1; } } There is no constructor and no complain from Cobertura. Now you need to test only the lines you really care about. ...
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How do I hide a menu item in the actionbar?

... 491 Get a MenuItem pointing to such item, call setVisible on it to adjust its visibility and then c...
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Get user info via Google API

...o array. $q = 'https://www.googleapis.com/oauth2/v1/userinfo?access_token=xxx'; $json = file_get_contents($q); $userInfoArray = json_decode($json,true); $googleEmail = $userInfoArray['email']; $googleFirstName = $userInfoArray['given_name']; $googleLastName = $userInfoArray['family_name']; ...
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Can I access a form in the controller?

... 91 If you want to pass the form to the controller for validation purposes you can simply pass it a...