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reference assignment is atomic so why is Interlocked.Exchange(ref Object, Object) needed?
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answered Feb 3 '10 at 16:20
Eric LippertEric Lippert
599k164164 gold badges11551155 silver badges20142014 bronze badges
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Converting A String To Hexadecimal In Java
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200
Here's a short way to convert it to hex:
public String toHex(String arg) {
return String.f...
CSS background image to fit width, height should auto-scale in proportion
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10 Answers
10
Active
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Docker how to change repository name or rename image?
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1085
docker image tag server:latest myname/server:latest
or
docker image tag d583c3ac45fd myname...
How to run a single test from a rails test suite?
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160
NOTE: This doesn't run the test via rake. So any code you have in Rakefile will NOT get executed...
How to get the day of week and the month of the year?
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answered Jan 27 '11 at 22:50
user113716user113716
291k5959 gold badges425425 silver badges431431 bronze badges
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Swift make method parameter mutable?
...passing in a pointer.
func reduceToZero(_ x: inout Int) {
while (x != 0) {
x = x-1
}
}
var a = 3
reduceToZero(&a)
print(a) // will print '0'
This can be particularly useful in recursion.
Apple's inout declaration guidelines can be found here.
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How to serve an image using nodejs
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2016 Update
Examples with Express and without Express that actually work
This question is over 5 years old but every answer has some problems.
TL;DR
Scroll down for examples to serve an image with:
express.static
express...
scale Image in an UIButton to AspectFit?
...ze.width;
CGFloat targetHeight = targetSize.height;
CGFloat scaleFactor = 0.0;
CGFloat scaledWidth = targetWidth;
CGFloat scaledHeight = targetHeight;
CGPoint thumbnailPoint = CGPointMake(0.0,0.0);
if (!CGSizeEqualToSize(imageSize, targetSize)) {
CGFloat widthFactor = targetWidth / width...
Constructing pandas DataFrame from values in variables gives “ValueError: If using all scalar values
...t;>> df = pd.DataFrame({'A': [a], 'B': [b]})
>>> df
A B
0 2 3
or use scalar values and pass an index:
>>> df = pd.DataFrame({'A': a, 'B': b}, index=[0])
>>> df
A B
0 2 3
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