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Ruby send vs __send__
...ss being manipulated defines. It could have overriden send.
Watch:
class Foo
def bar?
true
end
def send(*args)
false
end
end
foo = Foo.new
foo.send(:bar?)
# => false
foo.__send__(:bar?)
# => true
If you override __send__, Ruby will emit a warning:
warning: redefining ...
How to call methods dynamically based on their name? [duplicate]
... dispatch. It’s very easy in Ruby, just use public_send:
method_name = 'foobar'
obj.public_send(method_name) if obj.respond_to? method_name
If the method is private/protected, use send instead, but prefer public_send.
This is a potential security risk if the value of method_name comes from the...
What is the formal difference in Scala between braces and parentheses, and when should they be used?
...tod calls you should use the dot and parentheses.
val result = myInstance.foo(5, "Hello")
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Coding Practices which enable the compiler/optimizer to make a faster program
...ng slowdowns. For example, if your code looks like
void DoSomething(const Foo& foo1, const Foo* foo2, int numFoo, Foo& barOut)
{
for (int i=0; i<numFoo, i++)
{
barOut.munge(foo1, foo2[i]);
}
}
the compiler doesn't know that foo1 != barOut, and thus has to reload fo...
When is “i += x” different from “i = i + x” in Python?
... then x + y tries to call y.__radd__(x). So, in the case where you have
foo_instance += bar_instance
if Foo doesn't implement __add__ or __iadd__ then the result here is the same as
foo_instance = bar_instance.__radd__(bar_instance, foo_instance)
2In the expression foo_instance + bar_instance...
CSS attribute selector does not work a href
...ng.
a[href$='.pdf'] { /*css*/ }
JSFiddle: http://jsfiddle.net/UG9ud/
E[foo] an E element with a "foo" attribute (CSS 2)
E[foo="bar"] an E element whose "foo" attribute value is exactly equal to "bar" (CSS 2)
E[foo~="bar"] an E element whose "foo" attribute value is a list of whitespace-s...
How to check if one of the following items is in a list?
I'm trying to find a short way to see if any of the following items is in a list, but my first attempt does not work. Besides writing a function to accomplish this, is the any short way to check if one of multiple items is in a list.
...
如何编写一个独立的 PHP 扩展（译） - 更多技术 - 清泛网 - 专注C/C++及内核技术
... PHP 源码。
定义一个新扩展
我们给示例扩展命名为 “foobar”。
新扩展包含两个资源文件：foo.c 和 bar.c（还有一些头文件，但这些不只重要）。
示例扩展不引用任何外部的库（这点很重要，因为这样用户就不需要特别指定一...
In Python, how do I iterate over a dictionary in sorted key order?
...in a loop in a way very much like a dict, but it is not in anyway a dict!
foo = {
'a': 1,
'b': 2,
'c': 3,
}
print foo
>>> {'a': 1, 'c': 3, 'b': 2}
print foo.items()
>>> [('a', 1), ('c', 3), ('b', 2)]
print sorted(foo.items())
>>> [('a', 1), ('b...
How to fix “ImportError: No module named …” error in Python?
...
Do you have a file called __init__.py in the foo directory? If not then python won't recognise foo as a python package.
See the section on packages in the python tutorial for more information.
...