大约有 47,000 项符合查询结果(耗时:0.0444秒) [XML]

https://stackoverflow.com/ques... 

How to group dataframe rows into list in pandas groupby?

..., 'b':[1,2,5,5,4,6]}) df Out[1]: a b 0 A 1 1 A 2 2 B 5 3 B 5 4 B 4 5 C 6 In [2]: df.groupby('a')['b'].apply(list) Out[2]: a A [1, 2] B [5, 5, 4] C [6] Name: b, dtype: object In [3]: df1 = df.groupby('a')['b'].apply(list).reset_index(name='new') ...
https://stackoverflow.com/ques... 

How assignment works with Python list slice?

...ete, or replace contents from a list: Insertion: >>> a = [1, 2, 3] >>> a[0:0] = [-3, -2, -1, 0] >>> a [-3, -2, -1, 0, 1, 2, 3] Deletion: >>> a [-3, -2, -1, 0, 1, 2, 3] >>> a[2:4] = [] >>> a [-3, -2, 1, 2, 3] Replacement: >>> a [-...
https://stackoverflow.com/ques... 

How do I exchange keys with values in a dictionary?

... Python 2: res = dict((v,k) for k,v in a.iteritems()) Python 3 (thanks to @erik): res = dict((v,k) for k,v in a.items()) share | improve this answer | follow ...
https://stackoverflow.com/ques... 

Implement Stack using Two Queues

... 23 Answers 23 Active ...
https://stackoverflow.com/ques... 

Pandas: create two new columns in a dataframe with values calculated from a pre-existing column

... from pandas import * In [2]: def calculate(x): ...: return x*2, x*3 ...: In [3]: df = DataFrame({'a': [1,2,3], 'b': [2,3,4]}) In [4]: df Out[4]: a b 0 1 2 1 2 3 2 3 4 In [5]: df["A1"], df["A2"] = zip(*df["a"].map(calculate)) In [6]: df Out[6]: a b A1 A2 0 1 2 2...
https://stackoverflow.com/ques... 

map function for objects (instead of arrays)

... 38 Answers 38 Active ...
https://stackoverflow.com/ques... 

Python - Create list with numbers between 2 values?

...t returns a list so all you need is: >>> range(11, 17) [11, 12, 13, 14, 15, 16] In Python 3.x range is a iterator. So, you need to convert it to a list: >>> list(range(11, 17)) [11, 12, 13, 14, 15, 16] Note: The second number is exclusive. So, here it needs to be 16+1 = 17 E...
https://stackoverflow.com/ques... 

How to swap keys and values in a hash

... (in essence, by letting you access keys through values): {a: 1, b: 2, c: 3}.key(1) => :a If you want to keep the inverted hash, then Hash#invert should work for most situations: {a: 1, b: 2, c: 3}.invert => {1=>:a, 2=>:b, 3=>:c} BUT... If you have duplicate values, invert will...
https://stackoverflow.com/ques... 

Python, compute list difference

... 373 If the order does not matter, you can simply calculate the set difference: >>> set([...
https://stackoverflow.com/ques... 

Ruby Bundle Symbol not found: _SSLv2_client_method (LoadError)

...y-2.1.2.tar.gz... -> http://dqw8nmjcqpjn7.cloudfront.net/f22a6447811a81f3c808d1c2a5ce3b5f5f0955c68c9a749182feb425589e6635 Installing ruby-2.1.2... Installed ruby-2.1.2 to /Users/ryan/.rbenv/versions/2.1.2 share ...