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Convert list of dictionaries to a pandas DataFrame

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Avoiding memory leaks with Scalaz 7 zipWithIndex/group enumeratees

... Aaron NovstrupAaron Novstrup 20.1k77 gold badges6363 silver badges107107 bronze badges add a co...
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C#: how to get first char of a string?

... answered Oct 7 '10 at 5:01 Matthew FlaschenMatthew Flaschen 246k4343 gold badges477477 silver badges522522 bronze badges ...
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Sort a list from another list IDs

... answered Mar 7 '13 at 15:42 Denys DenysenkoDenys Denysenko 6,19911 gold badge1717 silver badges2929 bronze badges ...
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Assign multiple columns using := in data.table, by group

...ol1 col2 mean sum # 1: 1 1 hi hello 2.5 5 # 2: 2 2 hi hello 3.5 7 # 3: 3 3 hi hello 4.5 9 # 4: 1 4 hi hello 2.5 5 # 5: 2 5 hi hello 3.5 7 # 6: 3 6 hi hello 4.5 9 mynames = c("Name1", "Longer%") x[ , (mynames) := list(mean(b) * 4, sum(b) * 3), by = a] # a b col1 ...
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Difference between “!==” and “==!” [closed]

... | edited Sep 7 '12 at 14:28 BoltClock♦ 601k141141 gold badges12621262 silver badges12641264 bronze badges ...
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How do I make a matrix from a list of vectors in R?

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Simulating ENTER keypress in bash script

... answered Jun 7 '11 at 11:39 Tilman VogelTilman Vogel 7,76144 gold badges2929 silver badges2929 bronze badges ...
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What is Ruby equivalent of Python's `s= “hello, %s. Where is %s?” % (“John”,“Mary”)`

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How to get the first column of a pandas DataFrame as a Series?

... as pd >>> df = pd.DataFrame({'x' : [1, 2, 3, 4], 'y' : [4, 5, 6, 7]}) >>> df x y 0 1 4 1 2 5 2 3 6 3 4 7 >>> s = df.ix[:,0] >>> type(s) <class 'pandas.core.series.Series'> >>> ==========================================================...