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Is there a list of screen resolutions for all Android based phones and tablets? [closed]
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Device Inches ResolutionPX Density DPI ResolutionDP AspectRatios SysNavYorN ContentResolutionDP
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How does Google Instant work?
Any ideas on exactly how the new google instant search works? It seems to just be AJAX calls to the old search, but it's pretty hard to simplify Google that much. Anybody have speculations?
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Fast way of counting non-zero bits in positive integer
...'d use a lookup table. You can generate it at runtime:
counts = bytes(bin(x).count("1") for x in range(256)) # py2: use bytearray
Or just define it literally:
counts = (b'\x00\x01\x01\x02\x01\x02\x02\x03\x01\x02\x02\x03\x02\x03\x03\x04'
b'\x01\x02\x02\x03\x02\x03\x03\x04\x02\x03\x03\x...
What is a plain English explanation of “Big O” notation?
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Most popular screen sizes/resolutions on Android phones [closed]
...othing of how common a resolution is... just a table describing which one exists/categories?
– Ted
Mar 18 '14 at 15:03
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u'\ufeff' in Python string
...ecode the web page using the right codec, Python will remove it for you. Examples:
#!python2
#coding: utf8
u = u'ABC'
e8 = u.encode('utf-8') # encode without BOM
e8s = u.encode('utf-8-sig') # encode with BOM
e16 = u.encode('utf-16') # encode with BOM
e16le = u.encode('utf-16le') # e...
Python base64 data decode
...g piece of base64 encoded data, and I want to use python base64 module to extract information from it. It seems that module does not work. Can anyone tell me how?
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Fill remaining vertical space with CSS using display:flex
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Make it simple : DEMO
section {
display: flex;
flex-flow: column;
height: 300px;
}
header {
background: tomato;
/* no flex rules, it will grow */
}
div {
flex: 1; /* 1 and it will fill whole space left if no flex value are set to other children*...
How to access the last value in a vector?
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The nice thing with tail is that it works on dataframes too, unlike the x[length(x)] idiom.
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Looping in a spiral
...n need of an algorithm that would let him loop through the elements of an NxM matrix (N and M are odd). I came up with a solution, but I wanted to see if my fellow SO'ers could come up with a better solution.
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