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Getting the class name of an instance?
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Do you want the name of the class as a string?
instance.__class__.__name__
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Django : How can I see a list of urlpatterns?
...oin(p))" won't work because it's now a list of tuples instead of a list of strings, try "print(''.join(p[0]))".
– Cesar Canassa
Jul 9 '19 at 15:42
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Make sure that the controller has a parameterless public constructor error
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My deep in the bowels exception was a property type of 'string' when it should have been 'DateTime?'. Would not have looked for that had I not seen this answer. Thanks so very much.
– Jazzy
Apr 24 '17 at 19:25
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Duplicate symbols for architecture x86_64 under Xcode
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In my case, I just created a header file to define constant strings like this:
NSString *const AppDescriptionString = @"Healthy is the best way to keep fit";
I solved this scenario by using static:
static NSString *const AppDescriptionString = @"Healthy is the best way to keep fit...
How to elegantly ignore some return values of a MATLAB function?
... You can turn the warning off. End the line with this comment string %#ok Mlint will then ignore this. No warnings.
– user85109
Apr 25 '09 at 0:35
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How do you determine which backend is being used by matplotlib?
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Use the get_backend() function to obtain a string denoting which backend is in use:
>>> import matplotlib
>>> matplotlib.get_backend()
'TkAgg'
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Determine function name from within that function (without using traceback)
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functionNameAsString = sys._getframe().f_code.co_name
I wanted a very similar thing because I wanted to put the function name in a log string that went in a number of places in my code. Probably not the best way to do that, but here's a ...
Get and Set a Single Cookie with Node.js HTTP Server
...eCookies() using:
RegExp.prototype.exec - use regex to parse "name=value" strings
Here's the working example:
let http = require('http');
function parseCookies(str) {
let rx = /([^;=\s]*)=([^;]*)/g;
let obj = { };
for ( let m ; m = rx.exec(str) ; )
obj[ m[1] ] = decodeURIComponent( m[2]...
Java Try Catch Finally blocks without Catch
...e outer block.
public class TryCatchFinally {
public static void main(String[] args) throws Exception {
try{
System.out.println('A');
try{
System.out.println('B');
throw new Exception("threw exception in B");
}
finally
{
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can we use xpath with BeautifulSoup?
...y from the stream is more efficient than reading the response into a large string first. To do the same with the requests library, you want to set stream=True and pass in the response.raw object after enabling transparent transport decompression:
import lxml.html
import requests
url = "http://www...