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Good Hash Function for Strings
...unique hashes) So you could do something like:
int hash = 7;
for (int i = 0; i < strlen; i++) {
hash = hash*31 + charAt(i);
}
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In pure functional languages, is there an algorithm to get the inverse function?
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10 Answers
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Bootstrap: Open Another Modal in Modal
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20 Answers
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Is there any kind of hash code function in JavaScript?
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How to get a list of user accounts using the command line in MySQL?
...t entry.
– Matthew Scharley
Jul 16 '09 at 4:22
5
How to find the same info without sql query ??
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Scroll to bottom of Div on page load (jQuery)
...side of it.
Here is the correct version:
$('#div1').scrollTop($('#div1')[0].scrollHeight);
or jQuery 1.6+ version:
var d = $('#div1');
d.scrollTop(d.prop("scrollHeight"));
Or animated:
$("#div1").animate({ scrollTop: $('#div1').prop("scrollHeight")}, 1000);
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How can I use PowerShell with the Visual Studio Command Prompt?
...'s been driving me nuts that I have to punt to cmd.exe when running the VS2010 Command Prompt. I used to have a nice vsvars2008.ps1 script for Visual Studio 2008. Anyone have a vsvars2010.ps1 or something similar?
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Android How to adjust layout in Full Screen Mode when softkeyboard is visible
...ewById(android.R.id.content);
mChildOfContent = content.getChildAt(0);
mChildOfContent.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
public void onGlobalLayout() {
possiblyResizeChildOfContent();
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Is there a `pointer-events:hoverOnly` or similar in CSS?
...e it:
HTML
<div
id="toplayer"
class="layer"
style="
z-index: 20;
pointer-events: none;
background-color: white;
display: none;
"
>
Top layer
</div>
<div id="bottomlayer" class="layer" style="z-index: 10">Bottom layer</div>
CSS (unchanged)
.layer {
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Iterator Loop vs index loop [duplicate]
...terate over a std::vector:
1) index-based iteration
for (std::size_t i = 0; i != v.size(); ++i) {
// access element as v[i]
// any code including continue, break, return
}
Advantages: familiar to anyone familiar with C-style code, can loop using different strides (e.g. i += 2).
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