大约有 30,000 项符合查询结果（耗时：0.0640秒） [XML]
android get all contacts
...tentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
if ((cur != null ? cur.getCount() : 0) > 0) {
while (cur != null && cur.moveToNext()) {
String id = cur.getString(
cur.getColu...
Non greedy (reluctant) regex matching in sed?
I'm trying to use sed to clean up lines of URLs to extract just the domain.
22 Answers
...
Doctrine - How to print out the real sql, not just the prepared statement?
...ries I use
sudo vim /etc/mysql/my.cnf
and add those 2 lines:
general_log = on
general_log_file = /tmp/mysql.log
and restart mysql
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Is returning null bad design? [closed]
I've heard some voices saying that checking for a returned null value from methods is bad design. I would like to hear some reasons for this.
...
How to capture no file for fs.readFileSync()?
... good code practices here!
const content = await readFileAsync(path.join(__dirname, filePath), {
encoding: 'utf8'
})
return content;
}
Later can use this async function with try/catch from any other function:
const anyOtherFun = async () => {
try {
const fileContent = await rea...
Core dumped, but core file is not in the current directory?
While running a C program, It says "(core dumped)" but I can't see any files under the current path.
12 Answers
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How to use LocalBroadcastManager?
How to use/locate LocalBroadcastManager as described in google docs and Service broadcast doc ?
12 Answers
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Using jquery to get element's position relative to viewport
...swered Oct 14 '09 at 16:14
Agent_9191Agent_9191
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Python: Find in list
...n or generator expressions for that:
matches = [x for x in lst if fulfills_some_condition(x)]
matches = (x for x in lst if x > 6)
The latter will return a generator which you can imagine as a sort of lazy list that will only be built as soon as you iterate through it. By the way, the first one...
Sort array of objects by string property value
...ite your own comparison function:
function compare( a, b ) {
if ( a.last_nom < b.last_nom ){
return -1;
}
if ( a.last_nom > b.last_nom ){
return 1;
}
return 0;
}
objs.sort( compare );
Or inline (c/o Marco Demaio):
objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 :...