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How do I set the UI language in vim?
...ed, you want the :language command.
Note that putting this in your .vimrc or .gvimrc won’t help you with the menus in gvim, since their definition is loaded once at startup, very early on, and not re-read again later. So you really do need to set LC_ALL (or more specifically LC_MESSAGES) in your ...
Compile, Build or Archive problems with Xcode 4 (and dependencies)
This question has evolved over the past several weeks to cover more general issues with xcode4 (and upgrading projects form older xcode s).
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Commonly accepted best practices around code organization in JavaScript [closed]
As JavaScript frameworks like jQuery make client side web applications richer and more functional, I've started to notice one problem...
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error: ‘NULL’ was not declared in this scope
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NULL is not a keyword. It's an identifier defined in some standard headers. You can include
#include <cstddef>
To have it in scope, including some other basics, like std::size_t.
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What characters are allowed in DOM IDs? [duplicate]
Underscores seem fine. What about dashes? Other special characters?
5 Answers
5
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How do I break out of a loop in Scala?
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You have three (or so) options to break out of loops.
Suppose you want to sum numbers until the total is greater than 1000. You try
var sum = 0
for (i <- 0 to 1000) sum += i
except you want to stop when (sum > 1000).
What to do? ...
What are the differences between concepts and template constraints?
...ferences between the C++ full concepts proposal and template constraints (for instance, constraints as appeared in Dlang or the new concepts-lite proposal for C++1y ).
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How to check if string input is a number? [duplicate]
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Simply try converting it to an int and then bailing out if it doesn't work.
try:
val = int(userInput)
except ValueError:
print("That's not an int!")
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Why are C# interface methods not declared abstract or virtual?
C# methods in interfaces are declared without using the virtual keyword, and overridden in the derived class without using the override keyword.
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Java equivalent of unsigned long long?
... having access to a 64 bit unsigned integer, via unsigned long long int , or via uint64_t . Now, in Java longs are 64 bits, I know. However, they are signed.
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