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Find a Git branch containing changes to a given file
I have 57 local branches. I know I made a change to a certain file in one of them, but I'm not sure which one. Is there some kind of command I can run to find which branches contain changes to a certain file?
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Removing fields from struct or hiding them in JSON Response
...d then encodes that struct as JSON before sending back to the caller. I'd now like to allow the caller to be able to select the specific fields they would like returned by passing in a "fields" GET parameter.
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How to send HTTP request in java? [duplicate]
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I know others will recommend Apache's http-client, but it adds complexity (i.e., more things that can go wrong) that is rarely warranted. For a simple task, java.net.URL will do.
URL url = new URL("http://www.y.com/url");
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Multiline strings in JSON
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Now it ECMA-404 )) ecma-international.org/publications/files/ECMA-ST/ECMA-404.pdf
– gavenkoa
Mar 20 '17 at 9:06
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Output of git branch in tree like fashion
Right now, when I type "git branch"
6 Answers
6
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in iPhone App How to detect the screen resolution of the device
...ices will give a 2.0f and the iPhone 6 Plus (Retina HD) will give a 3.0f.
Now if you want to get the pixel width & height of the iOS device screen you just need to do one simple thing.
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale)...
VS2012 return to a normal TFS checkin window?
... seems to remove the popup window for TFS check-ins that was in VS2010. It now seems to take over the team explorer tab in my sidebar, and buries the important things - like which files I've changed. Is there any way to return to a normal popup window for check-ins in VS2012?
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Why is SSE scalar sqrt(x) slower than rsqrt(x) * x?
.../y - 1/x^2) but they will be equally complicated.
Let's look at 1/sqrt(y) now. You can try f(x) = x^2 - 1/y, but it will be equally complicated: dx = 2xy / (y*x^2 - 1) for instance.
One non-obvious alternate choice for f(x) is: f(x) = y - 1/x^2
Then: dx = -f/f' = (y - 1/x^2) / (2/x^3) = 1/2 * x * ...
The application may be doing too much work on its main thread
...re maths or simply sorting an array – Do it in a
different thread
Now there is a catch here, You will create a new Thread for doing
these operations and when you run your application, it will crash
saying “Only the original thread that created a view hierarchy can
touch its views“...
How to find the lowest common ancestor of two nodes in any binary tree?
...e for your other node in question, resulting in (steps not shown): {1, 2}
Now compare the two lists you made looking for the first element where the list differ, or the last element of one of the lists, whichever comes first.
This algorithm requires O(h) time where h is the height of the tree. In ...