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File inside jar is not visible for spring
... They are in the same jar, but I tried your solution with the same result: java.io.FileNotFoundException: class path resource [classpath*:my.config] cannot be resolved to URL because it does not exist
– BTakacs
Feb 15 '13 at 7:57
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Running JAR file on Windows
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Easiest route is probably upgrading or re-installing the Java Runtime Environment (JRE).
Or this:
Open the Windows Explorer, from the Tools select 'Folder Options...'
Click the File Types tab, scroll down and select JAR File type.
Press the Advanced button.
In the Edit File Type...
MySQL ON DUPLICATE KEY UPDATE for multiple rows insert in single query
...wered Apr 26 '10 at 15:26
Peter LangPeter Lang
49.3k2626 gold badges138138 silver badges152152 bronze badges
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Java: Multiple class declarations in one file
In Java, you can define multiple top level classes in a single file, providing that at most one of these is public (see JLS §7.6 ). See below for example.
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How to present a simple alert message in java?
...ng from .NET i am so used calling Alert() in desktop apps. However in this java desktop app, I just want to alert a message saying "thank you for using java" I have to go through this much suffering:
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How to get the current working directory in Java?
I want to access my current working directory using java.
22 Answers
22
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How do I create a file and write to it in Java?
What's the simplest way to create and write to a (text) file in Java?
33 Answers
33
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Switch on Enum in Java [duplicate]
Why can't you switch on an enum in Java? It seems simple enough to do and would make for some convenient code. Also this question could apply to String 's. You can switch on a char , but not a String ...?
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Hidden Features of Java
...Hidden Features of C# I wondered, What are some of the hidden features of Java?
100 Answers
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How to make a Java thread wait for another thread's output?
I'm making a Java application with an application-logic-thread and a database-access-thread.
Both of them persist for the entire lifetime of the application and both need to be running at the same time (one talks to the server, one talks to the user; when the app is fully started, I need both of t...