大约有 47,000 项符合查询结果(耗时:0.0598秒) [XML]
Force LF eol in git repo and working copy
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edited Mar 13 '16 at 10:11
answered Apr 2 '12 at 14:05
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Getting hold of the outer class object from the inner class object
...evel access - at least with the JDK I'm using.
EDIT: The name used (this$0) is actually valid in Java, although the JLS discourages its use:
The $ character should be used only in
mechanically generated source code or,
rarely, to access pre-existing names on
legacy systems.
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What's the best way to break from nested loops in JavaScript?
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1078
Just like Perl,
loop1:
for (var i in set1) {
loop2:
for (var j in set2) {
loop3:
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What's the advantage of a Java enum versus a class with public static final fields?
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answered Apr 2 '12 at 0:51
casablancacasablanca
64.3k55 gold badges121121 silver badges142142 bronze badges
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Parsing JSON using Json.net
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James Newton-King
42.9k2222 gold badges105105 silver badges127127 bronze badges
answered Dec 31 '08 at 10:37
Marc Gravell♦Marc Gravell
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Problems installing the devtools package
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Evan AadEvan Aad
4,90944 gold badges1919 silver badges3131 bronze badges
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How to correctly sort a string with a number inside? [duplicate]
...(key=natural_keys) sorts in human order
http://nedbatchelder.com/blog/200712/human_sorting.html
(See Toothy's implementation in the comments)
'''
return [ atoi(c) for c in re.split(r'(\d+)', text) ]
alist=[
"something1",
"something12",
"something17",
"something2",
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What is the easiest/best/most correct way to iterate through the characters of a string in Java?
...hod is a constant time operation.
String s = "...stuff...";
for (int i = 0; i < s.length(); i++){
char c = s.charAt(i);
//Process char
}
That's what I would do. It seems the easiest to me.
As far as correctness goes, I don't believe that exists here. It is all based on your...
How to check an Android device is HDPI screen or MDPI screen?
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density = getResources().getDisplayMetrics().density;
// return 0.75 if it's LDPI
// return 1.0 if it's MDPI
// return 1.5 if it's HDPI
// return 2.0 if it's XHDPI
// return 3.0 if it's XXHDPI
// return 4.0 if it's XXXHDPI
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Array to Hash Ruby
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360
a = ["item 1", "item 2", "item 3", "item 4"]
h = Hash[*a] # => { "item 1" => "item 2", "it...
