大约有 43,000 项符合查询结果（耗时：0.0586秒） [XML]
Gridview with two columns and auto resized images
...to stretch the column widths, set the spacing to 0 (or whatever you want), and set the number of columns to 2:
res/layout/main.xml
<?xml version="1.0" encoding="utf-8"?>
<FrameLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
...
Why are arrays of references illegal?
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Answering to your question about standard I can cite the C++ Standard §8.3.2/4:
There shall be no references to references, no arrays of references, and no pointers to references.
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Optimal number of threads per core
Let's say I have a 4-core CPU, and I want to run some process in the minimum amount of time. The process is ideally parallelizable, so I can run chunks of it on an infinite number of threads and each thread takes the same amount of time.
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Remove non-numeric characters (except periods and commas) from a string
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You could use preg_replace to swap out all non-numeric characters and the comma and period/full stop as follows:
$testString = '12.322,11T';
echo preg_replace('/[^0-9,.]+/', '', $testString);
The pattern can also be expressed as /[^\d,.]+/
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How do I redirect in expressjs while passing some context?
...gs. You'll need to ensure that the values are properly encodeURIComponent and decodeURIComponent.
app.get('/category', function(req, res) {
var string = encodeURIComponent('something that would break');
res.redirect('/?valid=' + string);
});
You can snag that in your other route by getting t...
Checkboxes in web pages – how to make them bigger?
The standard checkboxes rendered in most browsers are quite small and don’t increase in size even when a larger font is used. What is the best, browser-independent way to display larger checkboxes?
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What is the fastest way to get the value of π?
... fastest π I know of is the one with the digits hard coded. Looking at Pi and Pi[PDF], there are a lot of formulae.
Here is a method that converges quickly — about 14 digits per iteration. PiFast, the current fastest application, uses this formula with the FFT. I'll just write the formula, since...
Pointer to pointer clarification
...are doing is *ipp get the object at the address held in ipp which is ip1 and then assign to ip1 the value stored in ip2, which is the address of j.
Simply
& --> Address of
* --> Value at
share
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~x + ~y == ~(x + y) is always false?
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Assume for the sake of contradiction that there exists some x and some y (mod 2n) such that
~(x+y) == ~x + ~y
By two's complement*, we know that,
-x == ~x + 1
<==> -1 == ~x + x
Noting this result, we have,
~(x+y) == ~x + ~y
<==> ~(x+y) + (x+y) == ~x + ~y...
What is the best way to get all the divisors of a number?
...e dumb way (stopping at n/2) very cool, thank you!
– Andrea Ambu
Oct 5 '08 at 10:20
47
For those ...