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How do I compare two hashes?
...["c", 3]]
Hash[*difference.flatten]
=> {"c"=>3}
Doing it all in one operation and getting rid of the difference variable:
Hash[*(
(hash3.size > hash1.size) \
? hash3.to_a - hash1.to_a \
: hash1.to_a - hash3.to_a
).flatten]
=> {"c"=>3}
...
How to initialize List object in Java?
...them, I.E: to know which fits better your needs.
The 3 most commonly used ones probably are:
List<String> supplierNames1 = new ArrayList<String>();
List<String> supplierNames2 = new LinkedList<String>();
List<String> supplierNames3 = new Vector<String>();
...
Is < faster than
...s that the different jump instructions take the same amount of time. This one is a little tricky to answer, but here's what I can give: In the Intel Instruction Set Reference, they are all grouped together under one common instruction, Jcc (Jump if condition is met). The same grouping is made toget...
T-SQL: Deleting all duplicate rows but keeping one [duplicate]
...lightly different data but I do not care about that. I still need to keep one of these rows however. SELECT DISTINCT won't work because it operates on all columns and I need to suppress duplicates based on the key columns.
...
Initializing multiple variables to the same value in Java
...
String one, two, three;
one = two = three = "";
This should work with immutable objects. It doesn't make any sense for mutable objects for example:
Person firstPerson, secondPerson, thirdPerson;
firstPerson = secondPerson = third...
PHP: Move associative array element to beginning of array
...to join the original array to a new associative array using the known key (one).
$myArray = array('one' => $myArray['one']) + $myArray;
// or ['one' => $myArray['one']] + $myArray;
Array keys are unique, so it would be impossible for it to exist in two locations.
See further at the doc o...
What is the difference between the | and || or operators?
... the difference between those two usages? Are there any caveats when using one over the other or are they interchangeable?
...
How to concatenate string variables in Bash
...lo World
In general to concatenate two variables you can just write them one after another:
a='Hello'
b='World'
c="${a} ${b}"
echo "${c}"
> Hello World
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Swift - encode URL
...
Is no one else completely flabbergasted at how long this code is to do this? I mean that method name is already hell of long, even without choosing the allowed character set.
– thatidiotguy
Se...
Replace multiple characters in one replace call
...:
str.replace(/[#_]/g,'');
Fiddle
If you want to replace the hash with one thing and the underscore with another, then you will just have to chain. However, you could add a prototype:
String.prototype.allReplace = function(obj) {
var retStr = this;
for (var x in obj) {
retStr = ...