大约有 2,373 项符合查询结果（耗时：0.0215秒） [XML]
Regex for string not ending with given suffix
...p -vE "part[0-9]*$"
This results on my system:
pci-0000:00:0b.0-usb-0:1:1.0-scsi-0:0:0:0
If I only want the partitions I could do:
ls -1 /dev/disk/by-path/* | grep -P "\-usb\-" | grep -E "part[0-9]*$"
Where I get:
pci-0000:00:0b.0-usb-0:1:1.0-scsi-0:0:0:0-part1
pci-0000:00:0b.0-usb-0:1:1.0-...
pdf2htmlEX实现pdf转html - 开源 & Github - 清泛网 - 专注C/C++及内核技术
...html和pdf视图下的截图：
windows下载地址：pdf2htmlEX-v1.0-win32-static
本人开发的一个功能：文档在线阅读，要求能够支持移动终端浏览器在线阅读。考虑过将文档先转pdf，然后在将pdf转swf，利用flexpaper在前端浏览器访问。但是...
How can I create a border around an Android LinearLayout?
...a file called customborder.xml in your drawable folder:
<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
<corners android:radius="20dp"/>
<padding android:left="10dp" android:right="10dp"...
Using build types in Gradle to run same app that uses ContentProvider on one device
...build/generated/res/generated/debug/values/generated.xml
<?xml version="1.0" encoding="utf-8"?>
<resources>
<!-- Automatically generated file. DO NOT MODIFY -->
<!-- Values from default config. -->
<item name="account_type" type="string">your.syncadapter.ty...
Add a background image to shape in XML Android
...
Use following layerlist:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle" android:padding="10dp">
<corners
...
How can I run PowerShell with the .NET 4 runtime?
...ershell_ise.exe.config) file to have a chunk like this:
<?xml version="1.0" encoding="utf-8"?>
<configuration>
<startup>
<supportedRuntime version="v4.0.30319" />
</startup>
</configuration>
You can build .NET 4.0 applications that call PowerShell...
Why am I getting a “401 Unauthorized” error in Maven?
...ed, interferes with my new 0.1.2 version, as you suggest. Changing it to 0.1.0 ("earlier"), or 0.1.2a, or 0.1.3 ("later") results in the error I was dealing with before this one:
– aliteralmind
Jul 18 '14 at 18:46
...
Generate a random double in a range
... many double values in the desired range, if that range is larger than 0.0-1.0. If the desired range contains a larger number of values than the range 0.0-1.0 there will not be a value for each of them and they will never get generated. (By the pigeonhole principle!). Because of this Tunaki's soluti...
How do we control web page caching, across all browsers?
...itly required by some clients next to Expires). The Pragma is per the HTTP 1.0 spec for prehistoric clients. The Expires is per the HTTP 1.0 and 1.1 specs for clients and proxies. In HTTP 1.1, the Cache-Control takes precedence over Expires, so it's after all for HTTP 1.0 proxies only.
If you don't...
Fade In Fade Out Android Animation in Java
...
I know that this already has been answered but.....
<?xml version="1.0" encoding="utf-8"?>
<alpha xmlns:android="http://schemas.android.com/apk/res/android"
android:fromAlpha="1.0"
android:toAlpha="0.0"
android:duration="1000"
android:repeatCount="infinite"
...