大约有 800 项符合查询结果(耗时:0.0242秒) [XML]
App Inventor 2 ProCamera拓展:专业相机,提供滤镜、降噪、对焦等高级功能...
... API 配合使用而设计,可提供更多功能。扩展需要 Android 5.0 Lollipop 及更高版本才能运行。扩展功能:最新使用的API相机滤镜降噪模式...
专业相机专为与最新的 Android 相机 API 配合使用而设计,可提供更多功能。
扩展需要 Andr...
Access to Modified Closure (2)
... Could you please update your answer with respect to change in C# 5.0 spec? Just to make it a great wiki documentation regarding foreach loops in C#. There are already some good answers regarding change in C# 5.0 compiler treating foreach loops bit.ly/WzBV3L, but they aren't a wiki-like res...
Changing java platform on which netbeans runs
...e java installation in specified jdkhome: C:\Program Files (x86)\Java\jdk1.5.0_03\bin"; Do you want to try to use default version?"
– Enthusiastic
Nov 6 '15 at 11:54
1
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Display a float with two decimal places in Python
... and I need to output the values in a string with two decimal places (5 -> 5.00, 5.5 -> 5.50, etc). How can I do this in Python?
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Change font size of UISegmentedControl
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available in iOS 5.0 or later
– rakeshNS
Sep 13 '12 at 9:31
8
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Node.js: How to send headers with form data using request module?
...http://<your_url_here>';
var headers = {
'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.8; rv:24.0) Gecko/20100101 Firefox/24.0',
'Content-Type' : 'application/x-www-form-urlencoded'
};
var form = { username: 'user', password: '', opaque: 'someValue', logintype: '1'};
requ...
Does pandas iterrows have performance issues?
...r loop
letter number2
0 a 0.5
1 b 0.1
2 c 5.0
3 d 4.0
-- itertuple() --
100 loops, best of 3: 12.3 ms per loop
-- to_records() --
100 loops, best of 3: 7.29 ms per loop
-- Use group by --
100 loops, best of 3: 4.07 ms per loop
letter number2
1 a ...
Bordered UITextView
... of the -(void) viewDidLoad method
self.yourUITextView.layer.borderWidth = 5.0f;
self.yourUITextView.layer.borderColor = [[UIColor grayColor] CGColor];
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Core Data vs SQLite 3 [closed]
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With iOS 5.0 you get the added benefit of being able to use iCloud file-sync for free if you're using Core Data. If you're using SQLite directly it'll have to be a lot of manual tinkering and implementation to get it to sync across iC...
Round to 5 (or other number) in Python
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>>> for b in a:
... int(round(b/5.0)*5.0)
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