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How does java do modulus calculations with negative numbers?
Am I doing modulus wrong? Because in Java -13 % 64 is supposed to evaluate to -13 but I get 51 .
14 Answers
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How to find list intersection?
actual output: [1,3,5,6]
expected output: [1,3,5]
11 Answers
11
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Matplotlib scatter plot with different text at each data point
... could use annotate() while iterating over the values in n.
y = [2.56422, 3.77284, 3.52623, 3.51468, 3.02199]
z = [0.15, 0.3, 0.45, 0.6, 0.75]
n = [58, 651, 393, 203, 123]
fig, ax = plt.subplots()
ax.scatter(z, y)
for i, txt in enumerate(n):
ax.annotate(txt, (z[i], y[i]))
There are a lot of...
Removing duplicates from a list of lists
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>>> k = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4]]
>>> import itertools
>>> k.sort()
>>> list(k for k,_ in itertools.groupby(k))
[[1, 2], [3], [4], [5, 6, 2]]
itertools often offers the fastest and most powerful solutions to this kind of ...
How to delete multiple values from a vector?
...vector like: a = c(1:10) and I need to remove multiple values, like: 2, 3, 5
8 Answers
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How to deal with SettingWithCopyWarning in Pandas?
I just upgraded my Pandas from 0.11 to 0.13.0rc1. Now, the application is popping out many new warnings. One of them like this:
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C#位运算符（C#按位与、按位或 等） - 更多技术 - 清泛网 - 专注C/C++及内核技术
...如：10010001（二进制）&11110000等于10010000（二进制）。
3、位逻辑或运算
位逻辑或运算将两个运算对象按位进行或运算。或运算的规则是：1或1等1，1或0等于1，
0或0等于0。比如10010001（二进制）| 11110000（二进制）等于11110001...
How to round an average to 2 decimal places in PostgreSQL?
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283
PostgreSQL does not define round(double precision, integer). For reasons @Mike Sherrill 'Cat Rec...
The difference between bracket [ ] and double bracket [[ ]] for accessing the elements of a list or
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336
The R Language Definition is handy for answering these types of questions:
http://cran.r-pro...
Finding all possible combinations of numbers to reach a given sum
...ning, target, partial + [n])
if __name__ == "__main__":
subset_sum([3,9,8,4,5,7,10],15)
#Outputs:
#sum([3, 8, 4])=15
#sum([3, 5, 7])=15
#sum([8, 7])=15
#sum([5, 10])=15
This type of algorithms are very well explained in the following Standford's Abstract Programming lec...