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Invalid date format specification in gemspec
...update --system
Edit: You can also try (as suggested by ZeissS)
gem install rubygems-update
update_rubygems
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Map a network drive to be used by a service
...ve mappings are only restored on an interactive logon, which services typically don't perform.
The helper process approach can be pretty simple: just create a new service that maps the drive and starts the 'real' service. The only things that are not entirely trivial about this are:
The helper se...
Real world use of JMS/message queues? [closed]
...MS (ActiveMQ is a JMS broker implementation) can be used as a mechanism to allow asynchronous request processing. You may wish to do this because the request take a long time to complete or because several parties may be interested in the actual request. Another reason for using it is to allow mul...
Heroku 'Permission denied (publickey) fatal: Could not read from remote repository' woes
...nd it still didn't work. I ended up having to add an environment variable called HOME set to the directory my .ssh folder was in
– Justin
Dec 31 '13 at 21:31
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Why are primes important in cryptography?
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Most basic and general explanation: cryptography is all about number theory, and all integer numbers (except 0 and 1) are made up of primes, so you deal with primes a lot in number theory.
More specifically, some important cryptographic algorithms such as RSA critically depen...
How do I create a comma-separated list from an array in PHP?
...me. For example, maybe you want to quote each fruit and then separate them all by commas:
$prefix = $fruitList = '';
foreach ($fruits as $fruit)
{
$fruitList .= $prefix . '"' . $fruit . '"';
$prefix = ', ';
}
Also, if you just do it the "normal" way of appending a comma after each item (l...
How to $http Synchronous call with AngularJS
Is there any way to make a synchronous call with AngularJS?
7 Answers
7
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C# LINQ find duplicates in List
...erable.GroupBy(x => x.Key).Any(g => g.Count() > 1);
Find out if all values in an enumerable are unique :
var allUnique = enumerable.GroupBy(x => x.Key).All(g => g.Count() == 1);
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CSS two divs next to each other
...d="narrow">Narrow (200px)</div>
</div>
This is basically just scraping the surface of flexbox. Flexbox can do pretty amazing things.
For older browser support, you can use CSS float and a width properties to solve it.
#narrow {
float: right;
width: 200px;
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Java synchronized method lock on object, or method?
... anyway. That's a bit misleading. Synchronizing on the method is functionally equivalent to having a synchronized (this) block around the body of the method. The object "this" doesn't become locked, rather the object "this" is used as the mutex and the body is prevented from executing concurrentl...