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How to select last two characters of a string
I need to select last two characters from the variable, whether it is digit or letters.
9 Answers
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jQuery - select the associated label element of a input field [duplicate]
I have a set of input fields, some of them have labels associated, some not:
3 Answers
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How do I select child elements of any depth using XPath?
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If you are using the XmlDocument and XmlNode.
Say:
XmlNode f = root.SelectSingleNode("//form[@id='myform']");
Use:
XmlNode s = f.SelectSingleNode(".//input[@type='submit']");
It depends on the tool that you use. But .// will select any child, any depth from a reference node.
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Current executing procedure name
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You may try this:
SELECT OBJECT_NAME(@@PROCID)
Update: This command is still valid on SQL Server 2016.
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Throwing the fattest people off of an overloaded airplane.
...uch better. I use something quite like this for a recommendation engine (I select the top 200 items from a list of several million). I typically end up with only 50,000 or 70,000 items actually added to the heap.
I suspect that you'll see something quite similar: the majority of your candidates wil...
Count the occurrences of DISTINCT values
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SELECT name,COUNT(*) as count
FROM tablename
GROUP BY name
ORDER BY count DESC;
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Why there is no ForEach extension method on IEnumerable?
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Couldn't you just use Select instead of your Apply method? It seems to me that applying an action to each element and yielding it is exactly what Select does. E.g. numbers.Select(n => n*2);
– rasmusvhansen
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How to create relationships in MySQL
...s defined as the default storage engine,can check using command (mysql> SELECT @@default_storage_engine;)
– Arun
Feb 18 at 4:00
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How can I get a list of all functions stored in the database of a particular schema in PostgreSQL?
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SELECT n.nspname as "Schema", p.proname as "Name", pg_catalog.pg_get_function_result(p.oid) as "Result data type", pg_catalog.pg_get_function_arguments(p.oid) as "Argument data types", CASE WHEN p.proisagg THEN 'agg'...
Can I concatenate multiple MySQL rows into one field?
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You can use GROUP_CONCAT:
SELECT person_id, GROUP_CONCAT(hobbies SEPARATOR ', ')
FROM peoples_hobbies
GROUP BY person_id;
As Ludwig stated in his comment, you can add the DISTINCT operator to avoid duplicates:
SELECT person_id, GROUP_CONCAT(DISTINCT ...
