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Sockets: Discover port availability using Java
...rammatically determine the availability of a port in a given machine using Java?
10 Answers
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Java Interfaces/Implementation naming convention [duplicate]
...ck. Not ITruck because it isn't an ITruck it is a Truck.
An Interface in Java is a Type. Then you have DumpTruck, TransferTruck, WreckerTruck, CementTruck, etc that implement Truck.
When you are using the Interface in place of a sub-class you just cast it to Truck. As in List<Truck>. Putti...
JSON Array iteration in Android/Java
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If you're using the JSON.org Java implementation, which is open source, you can just make JSONArray implement the Iterable interface and add the following method to the class:
@Override
public Iterator iterator() {
return this.myArrayList.iterator()...
How to sort a HashMap in Java [duplicate]
...cess order. And finally if you're doing a lot of this you might check out Java 1.6 and NavigableMap, awesome stuff!
– Mark Bennett
Jan 5 '12 at 0:58
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How to check for a valid URL in Java?
What is the best way to check if a URL is valid in Java?
8 Answers
8
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If using maven, usually you put log4j.properties under java or resources?
...our classpath in your run configuration: Run->Run Configurations...->Java Application->New select the Classpath tab, select Advanced and browse to your src/resources directory.
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What are the big improvements between guava and apache equivalent libraries?
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First of, as javamonkey79 explained, while Google Guava and Apache Commons do share similar features, they also both have functionality that is absent from their counterpart. Thus, limiting yourself to only one library might be unwise.
T...
Rounding a double to turn it into an int (java)
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import java.math.*;
public class TestRound11 {
public static void main(String args[]){
double d = 3.1537;
BigDecimal bd = new BigDecimal(d);
bd = bd.setScale(2,BigDecimal.ROUND_HALF_UP);
// output is 3.15
Syste...
How do you declare an interface in C++?
...special Interface type-category in addition to abstract base classes in C#/Java is because C#/Java do not support multiple inheritance.
C++ supports multiple inheritance, and so a special type isn't needed. An abstract base class with no non-abstract (pure virtual) methods is functionally equiva...
What do 3 dots next to a parameter type mean in Java?
... that method.
See the "Arbitrary Number of Arguments" section here: http://java.sun.com/docs/books/tutorial/java/javaOO/arguments.html#varargs
In your example, you could call it as any of the following:
myMethod(); // Likely useless, but possible
myMethod("one", "two", "three");
myMethod("solo");
my...