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How to check a string for specific characters?
...(s):
print('Found')
else
print('Not found')
... or
chars = set('0123456789$,')
if any((c in chars) for c in s):
print('Found')
else:
print('Not Found')
[Edit: added the '$' in s answers]
share
|...
PHP: merge two arrays while keeping keys instead of reindexing?
...
You can simply 'add' the arrays:
>> $a = array(1, 2, 3);
array (
0 => 1,
1 => 2,
2 => 3,
)
>> $b = array("a" => 1, "b" => 2, "c" => 3)
array (
'a' => 1,
'b' => 2,
'c' => 3,
)
>> $a + $b
array (
0 => 1,
1 => 2,
2 => 3,
'a' =&...
Initializing a struct to 0
...ves less typing), and it is guaranteed to work, all members will be set to 0[Ref 1].
The second is more readable.
The choice depends on user preference or the one which your coding standard mandates.
[Ref 1] Reference C99 Standard 6.7.8.21:
If there are fewer initializers in a brace-e...
Alternatives to gprof [closed]
...
answered Dec 19 '09 at 5:26
Norman RamseyNorman Ramsey
184k5757 gold badges336336 silver badges517517 bronze badges
...
How can I pad a value with leading zeros?
...n for you, don't use this solution!
Potentially outdated: ECMAScript 2017 includes String.prototype.padStart and Number.prototype.toLocaleString is there since ECMAScript 3.1. Example:
var n=-0.1;
n.toLocaleString('en', {minimumIntegerDigits:4,minimumFractionDigits:2,useGrouping:false})
...
Secondary axis with twinx(): how to add to legend?
...
You can easily add a second legend by adding the line:
ax2.legend(loc=0)
You'll get this:
But if you want all labels on one legend then you should do something like this:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import rc
rc('mathtext', default='regular')
time =...
How to access pandas groupby dataframe by key
...group method:
In [21]: gb.get_group('foo')
Out[21]:
A B C
0 foo 1.624345 5
2 foo -0.528172 11
4 foo 0.865408 14
Note: This doesn't require creating an intermediary dictionary / copy of every subdataframe for every group, so will be much more memory-efficient that creating...
Why is the shovel operator (
...
Proof:
a = 'foo'
a.object_id #=> 2154889340
a << 'bar'
a.object_id #=> 2154889340
a += 'quux'
a.object_id #=> 2154742560
So << alters the original string rather than creating a new one. The reason for this is that in ruby a += b is syntactic short...
What's a redirect URI? how does it apply to iOS app for OAuth2.0?
...
Read this:
http://www.quora.com/OAuth-2-0/How-does-OAuth-2-0-work
or an even simpler but quick explanation:
http://agileanswer.blogspot.se/2012/08/oauth-20-for-my-ninth-grader.html
The redirect URI is the callback entry point of the app. Think about how OAuth fo...