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How would you make two s overlap?
... natural layout */
left: 75px;
top: 0px;
width: 300px;
height: 200px;
z-index: 2;
}
#content {
margin-top: 100px; /* Provide buffer for logo */
}
#links {
height: 75px;
margin-left: 400px; /* Flush links (with a 25px "padding") right of logo */
}
<div id="logo">
...
Why does Math.round(0.49999999999999994) return 1?
....1 This is a specification bug, for precisely this one pathological case.2 Java 7 no longer mandates this broken implementation.3
The problem
0.5+0.49999999999999994 is exactly 1 in double precision:
static void print(double d) {
System.out.printf("%016x\n", Double.doubleToLongBits(d));
}
...
how do I work around log4net keeping changing publickeytoken
... which uses a couple of frameworks which is dependent on log4net version 1.2.10.0. Today I tried to include a new framework which is dependent on log4net version 1.2.11.0, I've been stuck ever since:
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python tuple to dict
For the tuple, t = ((1, 'a'),(2, 'b'))
dict(t) returns {1: 'a', 2: 'b'}
6 Answers
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Is there a way to pass optional parameters to a function?
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The Python 2 documentation, 7.6. Function definitions gives you a couple of ways to detect whether a caller supplied an optional parameter.
First, you can use special formal parameter syntax *. If the function definition has a formal p...
Split list into multiple lists with fixed number of elements
...
214
I think you're looking for grouped. It returns an iterator, but you can convert the result to ...
Convert list to tuple in Python
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Peter Mortensen
26.5k2121 gold badges9292 silver badges122122 bronze badges
answered Oct 11 '12 at 9:15
rootroot
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From ND to 1D arrays
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283
Use np.ravel (for a 1D view) or np.ndarray.flatten (for a 1D copy) or np.ndarray.flat (for an ...
Write bytes to file
I have a hexadecimal string (e.g 0CFE9E69271557822FE715A8B3E564BE ) and I want to write it to a file as bytes. For example,
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Best way to find the intersection of multiple sets?
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From Python version 2.6 on you can use multiple arguments to set.intersection(), like
u = set.intersection(s1, s2, s3)
If the sets are in a list, this translates to:
u = set.intersection(*setlist)
where *a_list is list expansion
Note that...