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char类型移动跨平台踩过的坑 - C/C++ - 清泛网移动版 - 专注C/C++及内核技术
char类型移动跨平台踩过的坑CFLAG-fsigned-charchar强转int时，发现在x86平台下是按照有符号处理的，但是在ARM32下被当成了无符号导致问题，ARM64正常有符号。经调查，在PC上，char类型默认为signed-char,但是在一些嵌入式设备
char强转...
char类型移动跨平台踩过的坑 - C/C++ - 清泛网 - 专注C/C++及内核技术
char类型移动跨平台踩过的坑CFLAG-fsigned-charchar强转int时，发现在x86平台下是按照有符号处理的，但是在ARM32下被当成了无符号导致问题，ARM64正常有符号。经调查，在PC上，char类型默认为signed-char,但是在一些嵌入式设备
char强转...
How to check if a String is numeric in Java
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Note that the . in your regex will match any character, not just the decimal separator character.
– jqno
Jul 11 '09 at 8:16
9
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Parsing command-line arguments in C?
... write a program that can compare two files line by line, word by word, or character by character in C. It has to be able to read in command line options -l -w -i or -- ...
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How to get the number of characters in a std::string?
How should I get the number of characters in a string in C++?
12 Answers
12
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How can I get a file's size in C? [duplicate]
...ring, which I allocate using malloc() . Just writing malloc(10000*sizeof(char)); is IMHO a bad idea.
8 Answers
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Delete element in a slice
...d a slice while it is in range, it will induce some problem.
Old Answer:
chars := []string{"a", "a", "b"}
for i, v := range chars {
fmt.Printf("%+v, %d, %s\n", chars, i, v)
if v == "a" {
chars = append(chars[:i], chars[i+1:]...)
}
}
fmt.Printf("%+v", chars)
Expected :
[a a ...
Python glob multiple filetypes
... not possible. you can use only:
* matches everything
? matches any single character
[seq] matches any character in seq
[!seq] matches any character not in seq
use os.listdir and a regexp to check patterns:
for x in os.listdir('.'):
if re.match('.*\.txt|.*\.sql', x):
print x
...
Check if character is number?
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You could use comparison operators to see if it is in the range of digit characters:
var c = justPrices[i].substr(commapos+2,1);
if (c >= '0' && c <= '9') {
// it is a number
} else {
// it isn't
}
...
C语言结构体里的成员数组和指针 - C/C++ - 清泛网 - 专注C/C++及内核技术
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16
17
#include <stdio.h>
struct str{
int len;
char s[0];
};
struct foo {
struct str *a;
};
int main(int argc, char** argv) {
struct foo f={0};
if (f.a->s) {
printf( f.a->s);
}
return 0;
}
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