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Why does instanceof return false for some literals?

... 428 Primitives are a different kind of type than objects created from within Javascript. From the ...
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Why doesn't a python dict.update() return the object?

... | edited Sep 21 '09 at 14:21 answered Sep 21 '09 at 5:31 ...
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Are there disadvantages to using a generic varchar(255) for all text-based fields?

...single-byte content (e.g. ascii or latin1 characters). And likewise utf8mb4 character set causes the string to pad out to four bytes per character in memory. So a VARCHAR(255) in utf8 storing a short string like "No opinion" takes 11 bytes on disk (ten lower-charset characters, plus one byte for l...
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Copying text with color from Notepad++

... update As of 2019 NppExport is not included by default in the Notepad++ 64 bits version (github issue). You can download the 64 bits version of NppExport here: [github] share | improve this answer...
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High performance fuzzy string comparison in Python, use Levenshtein or difflib [closed]

...r().split("\t") diffl = difflib.SequenceMatcher(None, sr[3], sr[4]).ratio() lev = Levenshtein.ratio(sr[3], sr[4]) sor = 1 - distance.sorensen(sr[3], sr[4]) jac = 1 - distance.jaccard(sr[3], sr[4]) print diffl, lev, sor, jac I then plotted th...
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App Inventor 2 接入百度网盘API · App Inventor 2 中文网

...返回JSON,拿出想要的文件的fsid 【使用Web客户端】 4、获取文件信息,返回JSON,根据fsid取出dlink 【使用Web客户端】 5、根据dlink下载 【Web客户端】 6、下载效果展示 App Inventor 2 接入百度网盘API:文件上传 ...
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How do I use Django templates without the rest of Django?

... Daryl SpitzerDaryl Spitzer 113k6666 gold badges149149 silver badges165165 bronze badges 13 ...
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How can I parse a time string containing milliseconds in it with python?

... compie 9,1091414 gold badges5050 silver badges7373 bronze badges answered Mar 30 '09 at 17:49 DNSDNS ...
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git: patch does not apply

...ed Mar 13 '13 at 2:16 user1028904user1028904 4,36211 gold badge1212 silver badges77 bronze badges ...
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Apply multiple functions to multiple groupby columns

... similar dataframe as the one from above df = pd.DataFrame(np.random.rand(4,4), columns=list('abcd')) df['group'] = [0, 0, 1, 1] df a b c d group 0 0.418500 0.030955 0.874869 0.145641 0 1 0.446069 0.901153 0.095052 0.487040 0 2 0.843026 0.9361...