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json_encode sparse PHP array as JSON array, not JSON object

I have the following array in PHP: 4 Answers 4 ...
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MySQL: determine which database is selected?

... currently selected? This seems very basic but I couldn't find anything on php.net or stackoverflow (all results are for "no database selected"). ...
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PHP mkdir: Permission denied problem

I am trying to create a directory with PHP mkdir function but I get an error as follows: Warning: mkdir() [function.mkdir]: Permission denied in ... . How to settle down the problem? ...
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Make a link use POST instead of GET

...ng more than you already have. <form name="myform" action="handle-data.php" method="post"> <label for="query">Search:</label> <input type="text" name="query" id="query"/> <button>Search</button> </form> <script> var button = document.querySelec...
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Double not (!!) operator in PHP

What does the double not operator do in PHP? 6 Answers 6 ...
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PHP json_decode() returns NULL with valid JSON?

... On my server, it doesn't. And I can't call json_last_error() because it's PHP 5.2.9. That function appears on PHP 5.3.0. – Joel A. Villarreal Bertoldi Mar 9 '10 at 15:54 1 ...
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新闻传播中如何让沉默的数据说话 - 资讯 - 清泛网 - 专注C/C++及内核技术

...在,这一事故背后是不是有严重的安全责任,甚至是腐败问题;对于一些专业人士而言,可能还存在着危险品的安全管理、相关部门的职责划分、相关法律制度的执行是否到位等问题。针对这些特定的受众群存在的不同的关切点...
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Is it possible to delete an object's property in PHP?

...ght mind, convert an array into an object? It just makes no sense (even if PHP allows it). I will not encorage and spread bad programming habits by commenting on this :) No offense. – Yanick Rochon Mar 21 '14 at 2:54 ...
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JSON encode MySQL results

... $rows[] = $r; } print json_encode($rows); The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php. ...
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Are “elseif” and “else if” completely synonymous?

... From the PHP manual: In PHP, you can also write 'else if' (in two words) and the behavior would be identical to the one of 'elseif' (in a single word). The syntactic meaning is slightly different (if you're familiar with C, this i...