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What is a web service endpoint?
...This is a shorter and hopefully clearer answer...
Yes, the endpoint is the URL where your service can be accessed by a client application. The same web service can have multiple endpoints, for example in order to make it available using different protocols.
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What is the quickest way to HTTP GET in Python?
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Python 3:
import urllib.request
contents = urllib.request.urlopen("http://example.com/foo/bar").read()
Python 2:
import urllib2
contents = urllib2.urlopen("http://example.com/foo/bar").read()
Documentation for urllib.request and read.
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Using npm behind corporate proxy .pac
...username:password@servername:port/
Therefore to fix the problem I instead URL encoded the backslash, so entered this:
npm config set proxy "http://domain%5Cusername:password@servername:port/"
and with this the proxy access was fixed.
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Is it possible to make relative link to image in a markdown file in a gist?
...u.jpg)
Here's an example:
https://github.com/mark-anders/relative-image-url
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RESTfully design /login or /register resources?
...ki/Post/Redirect/Get
http://en.wikipedia.org/wiki/HTTP_303
Edit to address URL design concerns:
"How do I design my resources?" is an important question to me; "how do I design my URLs?" is a consideration in two areas:
URLs that users will see should not be too ugly and meaningful if possible;
if y...
How to specify the location with wget?
.... For this use just -O specifying full file path.
– murlakatamenka
Apr 5 at 21:47
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Have a variable in images path in Sass?
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Have you tried the Interpolation syntax?
background: url(#{$get-path-to-assets}/site/background.jpg) repeat-x fixed 0 0;
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How to go to a URL using jQuery? [duplicate]
How to go to a URL using jQuery or JavaScript.
4 Answers
4
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doGet and doPost in Servlets
...a bookmarkable request. Clicking a link, clicking a bookmark, entering raw URL in browser address bar, etcetera will all fire a HTTP GET request. If a Servlet is listening on the URL in question, then its doGet() method will be called. It's usually used to preprocess a request. I.e. doing some busin...
How do I load a file from resource folder?
...\xwork2\util\ClassLoaderUtil.java
src\main\resources\test.csv
// java.net.URL
URL url = ClassLoaderUtil.getResource("test.csv", YourCallingClass.class);
Path path = Paths.get(url.toURI());
List<String> lines = Files.readAllLines(path, StandardCharsets.UTF_8);
// java.io.InputStream
InputS...