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How can I remove 3 characters at the end of a string in php?
How can I remove 3 characters at the end of a string in php? "abcabcabc" would become "abcabc"!
3 Answers
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Best way to check if a URL is valid
I want to use PHP to check, if string stored in $myoutput variable contains a valid link syntax or is it just a normal text. The function or solution, that I'm looking for, should recognize all links formats including the ones with GET parameters.
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Equivalent of typedef in C#
...ions:
it will not work for primitive types
the derived type can still be casted to the original type, ie we can send it to a function receiving our original type, this defeats the whole purpose
we cannot derive from sealed classes (and ie many .NET classes are sealed)
The only way to achieve a ...
How do I get the last inserted ID of a MySQL table in PHP?
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mysql_(...) is deprecated in PHP >= 5.5 version.
– Iago
Oct 30 '14 at 2:12
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json_encode() escaping forward slashes
...ur enemy)
json_encode($str, JSON_UNESCAPED_SLASHES);
If you don't have PHP 5.4 at hand, pick one of the many existing functions and modify them to your needs, e.g. http://snippets.dzone.com/posts/show/7487 (archived copy).
Example Demo
<?php
/*
* Escaping the reverse-solidus character ("/"...
JavaScript isset() equivalent
In PHP you can do if(isset($array['foo'])) { ... } . In JavaScript you often use if(array.foo) { ... } to do the same, but this is not exactly the same statement. The condition will also evaluate to false if array.foo does exists but is false or 0 (and probably other values as well).
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AngularJs $http.post() does not send data
... serialization, which unfortunately some Web server languages—notably
PHP—do not unserialize natively.
Works like a charm.
CODE
// Your app's root module...
angular.module('MyModule', [], function($httpProvider) {
// Use x-www-form-urlencoded Content-Type
$httpProvider.defaults.header...
How to pass a single object[] to a params object[]
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A simple typecast will ensure the compiler knows what you mean in this case.
Foo((object)new object[]{ (object)"1", (object)"2" }));
As an array is a subtype of object, this all works out. Bit of an odd solution though, I'll agree.
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Subclassing a Java Builder class
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To solve the unchecked cast warning, see the solution suggested bellow among the other answers: stackoverflow.com/a/34741836/3114959
– Stepan Vavra
Jan 12 '16 at 11:00
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Overloaded method selection based on the parameter's real type
...e. More
generally, to force the compiler to select a specific overloading, cast actual parameters to the declared types of the formal parameters.
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