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jquery - fastest way to remove all rows from a very large table
...on. Kind of makes me want to do really ugly stuff like just hide the table and create a new one when I want to update it.
– morgancodes
Apr 6 '09 at 20:53
10
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Laravel Controller Subfolder routing
I'm new to Laravel. To try and keep my app organized I would like to put my controllers into subfolders of the controller folder.
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How to check if APK is signed or “debug build”?
As far as I know, in android "release build" is signed APK. How to check it from code or does Eclipse has some kinda of secret defines?
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How to make my font bold using css?
I'm very new to HTML and CSS and I was just wondering how I could make my font bold using CSS.
10 Answers
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Base constructor in C# - Which gets called first? [duplicate]
...yourself what has to happen. Imagine that you have base class named Animal and a derived class named Dog. The derived class adds some functionality to the base class. Therefore when the constructor of the derived class is executed the base class instance must be available (so that you can add new fu...
outline on only one border
... using an image to do that (GIF/PNG) that I would then use as a background and stretch it (repeat-x) and position a little off from the top of my block.
Recently, I discovered the outline CSS property, which is great! But seems to circle the whole block...
Is it possibly to use this outline proper...
java.lang.IllegalStateException: The specified child already has a parent
...ing the return statement should solve your problem.
You can keep the code and return the view if you don't want to regenerate view data, and onDestroyView() method you remove this view from its parent like so:
@Override
public void onDestroyView() {
super.onDestroyView();
i...
How do we use runOnUiThread in Android?
I'm new to Android and I'm trying to use the UI-Thread, so I've written a simple test activity. But I think I've misunderstood something, because on clicking the button - the app does not respond anymore
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Returning JSON from a PHP Script
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While you're usually fine without it, you can and should set the Content-Type header:
<?php
$data = /** whatever you're serializing **/;
header('Content-Type: application/json');
echo json_encode($data);
If I'm not using a particular framework, I usually allow some r...
How to simulate target=“_blank” in JavaScript
When a user clicks on a link, I need to update a field in a database and then open the requested link in a new window. The update is no problem, but I don't know how to open a new window without requiring them to click on another hyperlink.
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