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Java: random long number in 0
...ause directly using rng.nextLong() % n will be give uniform values (assume all bits are good). You can ignore that part if you want.
– kennytm
Mar 30 '10 at 20:07
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How to read a file line-by-line into a list?
... read from the file and processed, as suggested by @DevShark here. Holding all lines in a collection object is not a good idea if memory is a constraint or the file is large. The execution time is similar in both the approaches.
– Tirtha R
Mar 2 '18 at ...
Offset a background image from the right using CSS
...11/09/css3-background-position/
Update:
This feature is now supported in all major browsers, including mobile browsers.
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What are the differences between git remote prune, git prune, git fetch --prune, etc
...frustrated about this. The best way to look at is this. There are potentially three versions of every remote branch:
The actual branch on the remote repository
(e.g., remote repo at https://example.com/repo.git, refs/heads/master)
Your snapshot of that branch locally (stored under refs/remotes/...
Easiest way to compare arrays in C#
In Java, Arrays.equals() allows to easily compare the content of two basic arrays (overloads are available for all the basic types).
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How to count string occurrence in string?
...rn and elegant, but Vitimtk's solution is much more efficient. what do you all think of his code?
– TruMan1
Nov 4 '11 at 2:15
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JavaScript “new Array(n)” and “Array.prototype.map” weirdness
... objects in the array I believe the first map fails to run the function at all while the second manages to run.
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Uninstall Node.JS using Linux command line?
How do you uninstall node.js using the cmd line in linux?
14 Answers
14
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Google Guava isNullOrEmpty for collections
...eyard."
We don't believe that "is null or empty" is a question you ever really want to be asking about a collection.
If a collection might be null, and null should be treated the same as empty, then get all that ambiguity out of the way up front, like this:
Set<Foo> foos = NaughtyClass.getF...
What would cause an algorithm to have O(log n) complexity?
...er dividing n in half i times we'll have a value that is at most 1. The smallest i for which this is guaranteed is roughly log2 n, so if we have an algorithm that divides by 2 until the number gets sufficiently small, then we can say that it terminates in O(log n) steps.
An important detail is tha...