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“Could not find bundler” error
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Do a gem list bundler and see if it shows up. If it does not, you need to install it as listed in my answer.
– ardavis
Mar 19 '13 at 19:21
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Creating an object: with or without `new` [duplicate]
...llows two things:
Fine control over the lifetime of the object, since it does not go out of scope automatically; you must destroy it explicitly using the keyword delete;
Creating arrays with a size known only at runtime, since the object creation occurs at runtime. (I won't go into the specifics o...
Why do people use Heroku when AWS is present? What distinguishes Heroku from AWS? [closed]
...sy, good to use. The only problem is that I still have no idea what Heroku does...
15 Answers
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Java current machine name and logged in user?
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Does System.getProperty("user.name"); work on both windows and linux?
– Catfish
Apr 2 '14 at 20:15
5
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Alias with variable in bash [duplicate]
...llapsing a function into a oneline. function tail_ls { ls -l "$1" | tail } does not work without a ending like tail; }.
– Pablo Marin-Garcia
Feb 8 '12 at 10:26
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How to store printStackTrace into a string [duplicate]
...tring stackTrace = Throwables.getStackTraceAsString(e);
Internally, this does what @Zach L suggests.
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Algorithm to generate a crossword
...are on the board and check to see if the new word interferes.
If this word doesn't break the board, then place it there and go to step 3, otherwise, continue searching for a place (step 4).
Continue this loop until all the words are either placed or unable to be placed.
This makes a working, yet o...
How do you convert a byte array to a hexadecimal string, and vice versa?
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You're using SubString. Doesn't this loop allocate a horrible amount of string objects?
– Wim Coenen
Mar 6 '09 at 16:36
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Convert JSON String to JSON Object c#
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This does't work in case of the JObject this works for the simple json format data. I have tried my data of the below json format data to deserialize in the type but didn't get the response.
For this Json
{
"Customer": {
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“The run destination iOS Device is not valid for running the scheme”
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This bug exists in Xcode 11.4.1. Quitting Xcode does not fix it. Cmon Apple
– vikzilla
May 14 at 7:00
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