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C++ SFINAE examples?
... @akim: yeah its what I thought -> C99. This is not allowed in C++, here is what you get with a modern compiler : error C2466: cannot allocate an array of constant size 0
– v.oddou
Jun 16 '14 at 1:31
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Learn C first before learning Objective-C [closed]
...xample is a brilliant feature)... and I really like Obj-C (much more than C++! I hate the C++ syntax and some language features are plain overkill and lead to bad development patterns IMHO); however, when I sometimes re-write Obj-C code of my colleagues (and I really only do so, if I think this is ...
Difference between pre-increment and post-increment in a loop?
...tResult = i++;
Assert( postIncrementtResult == 3 );
Assert( i == 4 );
In C++, the pre-increment is usually preferred where you can use either.
This is because if you use post-increment, it can require the compiler to have to generate code that creates an extra temporary variable. This is because b...
How can I get a file's size in C++? [duplicate]
...uestion to this one .
What is the most common way to get the file size in C++?
Before answering, make sure it is portable (may be executed on Unix, Mac and Windows),
reliable, easy to understand and without library dependencies (no boost or qt, but for instance glib is ok since it is portable libra...
The static keyword and its various uses in C++
The keyword static is one which has several meanings in C++ that I find very confusing and I can never bend my mind around how its actually supposed to work.
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Is it safe to delete a void pointer?
...cific types.
As mentioned in other answers, this is undefined behavior in C++. In general it is good to avoid undefined behavior, although the topic itself is complex and filled with conflicting opinions.
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Where and why do I have to put the “template” and “typename” keywords?
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(See here also for my C++11 answer)
In order to parse a C++ program, the compiler needs to know whether certain names are types or not. The following example demonstrates that:
t * f;
How should this be parsed? For many languages a compiler do...
Why is volatile not considered useful in multithreaded C or C++ programming?
...le unnecessary. We can just remove the volatile qualifier entirely.
Since C++11, atomic variables (std::atomic<T>) give us all of the relevant guarantees.
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What is the “assert” function?
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"assert usually raises an exception" -- in C++ it does not rise "exception" it calls abort... it is little bit different.
– Artyom
Oct 15 '09 at 10:55
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Passing variable arguments to another function that accepts a variable argument list
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Maybe throwin a rock in a pond here, but it seems to work pretty OK with C++11 variadic templates:
#include <stdio.h>
template<typename... Args> void test(const char * f, Args... args) {
printf(f, args...);
}
int main()
{
int a = 2;
test("%s\n", "test");
test("%s %d %d %p\n"...