大约有 41,800 项符合查询结果（耗时：0.0128秒） [XML]
node.js hash string?
...');
var hash = sha1("my message");
console.log(hash); // 104ab42f1193c336aa2cf08a2c946d5c6fd0fcdb
or
$ npm install md5
and then
var md5 = require('md5');
var hash = md5("my message");
console.log(hash); // 8ba6c19dc1def5702ff5acbf2aeea5aa
(MD5 is insecure but often used by services like ...
Sequence-zip function for c++11?
... answered Sep 12 '13 at 18:19
aaronmanaaronman
16.8k55 gold badges5656 silver badges7676 bronze badges
...
Setting the Vim background colors
... answered Jun 8 '12 at 11:58
AA.AA.
4,1302626 silver badges3535 bronze badges
...
Ternary operator is twice as slow as an if-else block?
... dword ptr [edi+4],0
0000007b 7E 2D jle 000000AA
0000007d 8B 44 B7 08 mov eax,dword ptr [edi+esi*4+8]
60: {
61: value += i > 0 ? 2 : 3;
00000081 85 C0 test eax,eax
00000083 7F 07 ...
How do I tell git to always select my local version for conflicted merges on a specific file?
...it -m "prepare myBranch with .gitattributes merge strategy"
[myBranch ec202aa] prepare myBranch with .gitattributes merge strategy
We have a .gitattributes file defined in the dirWithCopyMerge directory (defined only in the branch where the merge will occurs: myBranch), and we have a .git\config f...
What is the Ruby (spaceship) operator?
...d Jan 11 '13 at 14:02
Anil MauryaAnil Maurya
2,13011 gold badge1919 silver badges2727 bronze badges
...
Performing Breadth First Search recursively
... qq = bfsNumForest(i+1, q)
val (bb, qqq) = qq.dequeue
val (aa, tss) = qqq.dequeue
tss.enqueue[org.dg.collection.BFSNumber.Tree[Int]](Node(i, aa, bb))
}
}
}
def bfsNumTree[T](t: Tree[T]): Tree[Int] = {
val q = Queue.Empty.enqueue[Tree[T]](t)
val qq = bfsNumForest(1,...
Escaping regex string
... answered Nov 11 '08 at 9:37
ddaaddaa
45.6k77 gold badges4848 silver badges5555 bronze badges
...
Difference between modes a, a+, w, w+, and r+ in built-in open function?
...he writes are always positioned at the end.
– Antti Haapala
Aug 20 '16 at 9:58
11
@And I believe ...
Merge 2 arrays of objects
..."name") );
// ----
// ES6 one-liner
var merge = (a, b, p) => a.filter( aa => ! b.find ( bb => aa[p] === bb[p]) ).concat(b);
console.log( "ES6 one-liner", merge(odd, even, "name") );
// Results
// ( stuff in the "b" array replaces things in the "a" array )
// [
// {
// "name":...