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iOS app, programmatically get build version
Is there a way to programmatically get the build version of my app? I need to be able to detect when the user has updated the app through the AppStore, in order to execute some code for adjustments
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How to run `rails generate scaffold` when the model already exists?
...'parent_module/controller_name'.
This generates a controller class in app/controllers and invokes helper,
template engine and test framework generators.
To create your resource, you'd use the resource generator, and to create a migration, you can also see the migration generator (see, t...
How to create .ipa file using Xcode?
Please tell me the complete procedure to build my app & use it on real iPhone.
9 Answers
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How to fix Error: “Could not find schema information for the attribute/element” by creating schema
I have a windows forms application written in VS2010 with C# and get the following errors in the app.config file:
10 Answ...
App Inventor 2 中文网
... 您的浏览器可能不兼容！ 要使用 Android 版 App Inventor 2，您必须使用兼容的浏览器。 目前支持的浏览器有： Google Chrome 29+ Safari 6.1+ Firefox 23+ 关于App Inventor 2 ...
解决IIS发布时global_asax的dll 的CS0433冲突问题 - 环境配置 - 清泛IT社区，为创新赋能！
Server Error in '/' Application.Compilation ErrorDescription: An error occurred during the compilation of a resource required to service this request. Please review the following specific error details and modify your source code appropriately.
Compiler Error Message: CS0433: The type 'ASP.globa...
Error: Argument is not a function, got undefined
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Remove the [] from the name ([myApp]) of module
angular.module('myApp', [])
And add ng-app="myApp" to the html and it should work.
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AppSettings get value from .config file
...is works for me:
string value = System.Configuration.ConfigurationManager.AppSettings[key];
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Format numbers in django templates
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Django's contributed humanize application does this:
{% load humanize %}
{{ my_num|intcomma }}
Be sure to add 'django.contrib.humanize' to your INSTALLED_APPS list in the settings.py file.
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How do I get the name of the current executable in C#?
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System.AppDomain.CurrentDomain.FriendlyName
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