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Highlight a word with jQuery
...nburkard.de/blog/programming/javascript/… In this case it was not a good idea to copy the code here; the link points to the latest version (now :)).
– Lerin Sonberg
Jan 24 '15 at 9:56
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jQuery autocomplete tagging plug-in like StackOverflow's input tags? [closed]
...it's more likely to be cached on user's machines, so my vote goes for good idea.
In the five years since I first offered this, it has become common wisdom.
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A generic list of anonymous class
...ew List<T>(elements);
}
var list = CreateList(o, o1);
You get the idea :)
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Variable is accessed within inner class. Needs to be declared final
...f you can use it when building Android app, so Googling it might be a good idea :-)
– Kevin Zhao
Oct 12 '15 at 20:15
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JavaScript hashmap equivalent
... this simple solution still requires more explanations. Let me clarify the idea in a Q&A form.
Your solution doesn't have a real hash. Where is it???
JavaScript is a high-level language. Its basic primitive (Object) includes a hash table to keep properties. This hash table is usually written in ...
Are email addresses case sensitive?
...ail address is converted to lower case prior to sending. That's not a good idea, since there is a small chance it will not get delivered. So how you treat it depends on what the consequences of error are and what you're doing with the email addresses at that time (collating a list of unique addresse...
How do you design object oriented projects? [closed]
...ode. In this case, use cases or user stories provide are a good high level idea, in particular for GUI apps. For command line apps, and in particular libraries, try to write "program stories" in which you code against the library you have to develop and check how it looks. These programs will become...
Change project name on Android Studio
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You can change the name that is shown in the title bar in the file ".idea/.name".
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VIM + Syntastic: how to disable the checker?
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This is quite handy, thanks .. I have added the idea to my config. +1
– jdt
Apr 17 '14 at 3:41
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How to find the kth smallest element in the union of two sorted arrays?
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This is not a real proof, but the idea behind the algorithm is that we maintain i + j = k, and find such i and j so that a[i-1] < b[j-1] < a[i] (or the other way round). Now since there are i elements in 'a' smaller than b[j-1], and j-1 elements in 'b' ...