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Backbone.js get and set nested object attribute

I have a simple question about Backbone.js' get and set functions. 9 Answers 9 ...
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Should I use multiplication or division?

... Thanks for the tip on using the time command for benchmarking! – Edmundito Oct 22 '08 at 17:11 2 ...
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Collection versus List what should you use on your interfaces?

... the question as to why not List<T>, The reasons are future-proofing and API simplicity. Future-proofing List<T> is not designed to be easily extensible by subclassing it; it is designed to be fast for internal implementations. You'll notice the methods on it are not virtual and so can...
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How do you rename a MongoDB database?

There's a typo in my MongoDB database name and I'm looking to rename the database. 10 Answers ...
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Checking if a string can be converted to float in Python

I've got some Python code that runs through a list of strings and converts them to integers or floating point numbers if possible. Doing this for integers is pretty easy ...
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Check if two linked lists merge. If so, where?

...wed" it was meant "you may change but in the end they should be restored", and we could iterate the lists exactly twice the following algorithm would be the solution. First, the numbers. Assume the first list is of length a+c and the second one is of length b+c, where c is the length of their co...
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Understanding Canvas and Surface concepts

I'm struggling to understand the process of drawing to SurfaceView and therefore the whole Surface / Canvas / Bitmap system, which is used in Android. ...
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Visual Studio Project vs. Solution

... A solution is a container for projects, and tracks dependencies between projects. share | improve this answer | follow | ...
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How to center canvas in html5

...center according to the size of the browser window. The canvas is 800x600. And if the window gets below 800x600, it should resize as well(but that's not very important at the moment) ...
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Are 2^n and n*2^n in the same time complexity?

... answer this question. The definition is that f(x) belongs to O(g(x)) if and only if the limit limsupx → ∞ (f(x)/g(x)) exists i.e. is not infinity. In short this means that there exists a constant M, such that value of f(x)/g(x) is never greater than M. In the case of your question let f(n) ...