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Java null check why use == instead of .equals()
...l,
// so one of the first checks inside the `Foo#equals` method will
// disallow the equality because it sees that `other` == null
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How to go to a specific element on page? [duplicate]
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+1 for the native scrollIntoView which i didnt know at all. for a moment i thought it was jquery. :)
– naveen
Jan 26 '11 at 6:15
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Get URL query string parameters
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This is actually the best answer based on the question. The other answers only get the current URI whereas the question only specifies "from URL".
– Chris Harrison
Aug 29 '13 at 5:38
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Replacing a char at a given index in string? [duplicate]
...es what I need. I suppose the CPU cost is high, but the string sizes are small so it's all ok
7 Answers
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What exactly does a jar file contain?
As an intern, I use company code in my projects and they usually send me a jar file to work with. I add it to the build path in Eclipse and usually all is fine and dandy.
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Handling InterruptedException in Java
... way to do it?
You've probably come to ask this question because you've called a method that throws InterruptedException.
First of all, you should see throws InterruptedException for what it is: A part of the method signature and a possible outcome of calling the method you're calling. So start b...
what does -webkit-transform: translate3d(0,0,0); exactly do? Apply to body?
... the body or individual elements? It seems to improve scroll events drastically.
5 Answers
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What is the best way to test for an empty string with jquery-out-of-the-box?
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Based on David's answer I personally like to check the given object first if it is a string at all. Otherwise calling .trim() on a not existing object would throw an exception:
function isEmpty(value) {
return typeof value == 'string' && !value.t...
do N times (declarative syntax)
...based on Array.forEach, without any library, just native vanilla.
To basically call something() 3 times, use:
[1,2,3].forEach(function(i) {
something();
});
considering the following function:
function something(){ console.log('something') }
The outpout will be
something
something
somethi...
How do I work around JavaScript's parseInt octal behavior?
...ust be warned, Number('08.123') will produce 8.123 as its output. If you really want an integer, don't use Number (or pattern-match your input to ensure integers only).
– Jason S
May 11 '09 at 22:22
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