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when using AlertDialog.Builder with EditText, the Soft Keyboard doesn't pop
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Thank you so much. I've searched for a while now and this is the way you want to go. All the OnFocusChangeListener approaches seem to much to me and cause trouble. You have to create the AlertDialog from the AlertDialog.Builder!
– philipp
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Java RegEx meta character (.) and ordinary dot?
... RegEx, how to find out the difference between . (dot) the meta character and the normal dot as we using in any sentence. How to handle this kind of situation for other meta characters too like ( * , + , \d ,...)
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Making a request to a RESTful API using python
...nt to fetch binary content
# Loads (Load String) takes a Json file and converts into python data structure (dict or list, depending on JSON)
jData = json.loads(myResponse.content)
print("The response contains {0} properties".format(len(jData)))
print("\n")
for key in jData:
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Creating and playing a sound in swift
... Did you try to compile the code? I am getting error "Cannot convert the extression's type 'Unmanaged <CFURL>!' to type 'CFString'" from this line "let soundURL = CFBundleCopyResourceURL(CFBundleGetMainBundle(), "Cha-Ching", "aiff", nil)"
– bpolat
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How do I write a custom init for a UIView subclass in Swift?
Say I want to init a UIView subclass with a String and an Int .
5 Answers
5
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Validating URL in Java
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Using only standard API, pass the string to a URL object then convert it to a URI object. This will accurately determine the validity of the URL according to the RFC2396 standard.
Example:
public boolean isValidURL(String url) {
try {
new URL(url).toURI();
} catch (Ma...
Pass An Instantiated System.Type as a Type Parameter for a Generic Class
...generic method which does all of the work you want to do with the generic, and call that with reflection.
– Jon Skeet
Nov 5 '08 at 21:30
1
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Predicate in Java
... someone guide me to any tutorial or conceptual explanation of Predicate and its implementation in Java?
4 Answers
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Removing duplicate objects with Underscore for Javascript
...ses a deep object comparison to check for duplicates (without resorting to converting to JSON, which is inefficient and hacky)
var newArr = _.filter(oldArr, function (element, index) {
// tests if the element has a duplicate in the rest of the array
for(index += 1; index < oldArr.length;...
How to check if type of a variable is string?
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isinstance(s, basestring)
basestring is the abstract superclass of str and unicode. It can be used to test whether an object is an instance of str or unicode.
In Python 3.x, the correct test is
isinstance(s, str)
The bytes class isn't considered a string type in Python 3.
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