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Getting the last argument passed to a shell script
$1 is the first argument.
$@ is all of them.
27 Answers
27
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Comma separator for numbers in R?
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135
You can try either format or prettyNum, but both functions return a vector of characters. I'd ...
How does the socket API accept() function work?
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142
Your confusion lies in thinking that a socket is identified by Server IP : Server Port. When ...
How to use JUnit and Hamcrest together?
...tchers . At the same time there are some other matchers in hamcrest-all-1.1.jar in org.hamcrest.Matchers . So, where to go? Shall I explicitly include hamcrest JAR into the project and ignore matchers provided by JUnit?
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How to check the version before installing a package using apt-get?
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10 Answers
10
Active
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How to easily initialize a list of Tuples?
...s you do this:
var tupleList = new List<(int, string)>
{
(1, "cow"),
(5, "chickens"),
(1, "airplane")
};
If you don't need a List, but just an array, you can do:
var tupleList = new(int, string)[]
{
(1, "cow"),
(5, "chickens"),
(1, "airplane")
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Angular.js ng-repeat across multiple tr's
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169
Using ng-repeat on tbody appears to be valid see this post.
Also a quick test through an html...
Rounding float in Ruby
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182
When displaying, you can use (for example)
>> '%.2f' % 2.3465
=> "2.35"
If you wan...
Adding a new array element to a JSON object
...Object, then stringify back to JSON
var jsonStr = '{"theTeam":[{"teamId":"1","status":"pending"},{"teamId":"2","status":"member"},{"teamId":"3","status":"member"}]}';
var obj = JSON.parse(jsonStr);
obj['theTeam'].push({"teamId":"4","status":"pending"});
jsonStr = JSON.stringify(obj);
// "{"theTeam...
Simpler way to create dictionary of separate variables?
...) for name in ['some','list','of','vars'] )
Example
>>> some= 1
>>> list= 2
>>> of= 3
>>> vars= 4
>>> dict( (name,eval(name)) for name in ['some','list','of','vars'] )
{'list': 2, 'some': 1, 'vars': 4, 'of': 3}
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